Math help please i have discalcula

I really really need help someone!! )):

yaroslaw [1]

diameter is 15 meters then radius is 15/2 = 7.5 meters

so the amplitude is 7.5 m and height will oscillate with amplitude 7.5 m above and below the center.

midline of the oscillation will be 7.5 m

the wheel.take 8 minutes to complete revolution then it means the height will oscillate with a period of 8 minutes

3 0

3 years ago

Describe how you would use a yardstick to measure a rug

Dafna11 [192]

Well first of this makes sense because you need to make sure your rug will fit. So anyways, first lay your rug out on a flat surface, grab your yardstick, lay it on the rug to find the length and then the width. you then know the size of your rug(assuming its square). You can do the same thing in the room you want it in.

6 0

3 years ago

Can i get help with this plss

damaskus [11]

49.32 multiply 0.09 x 548 to get the answe

3 0

3 years ago

Read 2 more answers

a circle has a center (3,5) and a diameter AB. The coordinates of A are (-4,6). what are the coordinates of B?

Kruka [31]

Find the length of the radius.

$r= \sqrt{(3-(-4))^2+(5-6)^2}
\\r = \sqrt{7^2+(-1)^2}
\\r= \sqrt{50} 
\\ r=5 \sqrt{2}$

Find the length of the diameter.

d = 2r = 2 × 5√2 = 10√2

Point B must lie on a line AC, where C is a center of a circle.
Find equation of line AC.
A(–4, 6), C(3, 5)

$y-y_1= \frac{y_2-y_1}{x_2-x_1}(x-x_1)
\\y-6= \frac{5-6}{3-(-4)} (x-(-4))
\\y-6=- \frac{1}{7} (x+4)
\\7y-42=-x-4
\\x+7y-38=0$

The distance from B(x, y) to C(3, 5) is 5√2.
$\sqrt{(x-3)^2+(y-5)^2}=5 \sqrt{2} 
 \\(x-3)^2+(y-5)^2=(5 \sqrt{2})^2 
\\(x-3)^2+(y-5)^2=50$

Solve system of equations.
$x+7y-38=0
\\(x-3)^2+(y-5)^2=50
\\
\\x=38-7y
\\(38-7y-3)^2+(y-5)^2=50
\\(35-7y)^2+(y-5)^2=50
\\1225-490y+49y^2+y^2-10y+25-50=0
\\50y^2-500y+1200=0
\\y^2-10y+24=0
\\y^2-6y-4y+24=0
\\y(y-6)-4(y-6)=0 \\(y-6)(y-4)=0 \\y_1=6,y_2=4
$

$x_1=38-7y_1=38-7 \times 6 = 38-42=-4
\\x_2=38-7y_2=38-7 \times 4 = 38-28=10
$

Point B could have coordinates
$\\
\\(x_1,y_1)=(-4,6),(x_2,y_2)=(10,4)
$

But (–4, 6) are the coordinates of point A.
Therefore, point B has coordinates (10,4).

8 0

3 years ago

I will give brainliest to the fastest helpful answer! :) A figure is located at (0, 0), (−3, −4), and (−3, 0) on a coordinate pl

yulyashka [42]

The 3-D shape would be created if the figure was rotated around the x-axis is a cone

<h3>What are 3-D shapes?</h3>

3-D shapes (short form of 3-Dimensional shapes) are shapes that have width, length and height

<h3>How to determine the 3-D shape?</h3>

The coordinates are given as:

(0, 0), (-3, -4) and (-3, 0)

When the above coordinates are plotted on a coordinate plane and the points are connected;

We can see that the points form a right-triangle

See attachment for the shape

As a general rule

Rotating a right-triangle across the x-axis would form a cone

Hence, the 3-D shape would be created if the figure was rotated around the x-axis is a cone