Answer:
A
Step-by-step explanation:
The equation will be in the form
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, 5) and (x₂, y₂ ) = (2.5, 0) ← 2 points on the line
m = 
= - 2
The line crosses the y- axis at (0, 5) ⇒ c = 5
y = - 2x + 5 or
y = 5 - 2x → A
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
Answer:
The equation of the line would be y = 4/9x
Step-by-step explanation:
In order to find the equation, we first need to find the slope. We can do this by using the slope equation with the points.
m(slope) = (y2 - y1)/(x2 - x1)
m = (9 - 0)/(4 - 0)
m = 9/4
Now that we have this, we can use point-slope form along with one of the points to get the equation.
y - y1 = m(x -x1)
y - 0 = 4/9(x - 0)
y = 4/9x
You have to go through your x-axis and up or down you y-axis and then determine if the end point are on the right plot form
