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Reptile [31]
3 years ago
6

5 whole numbers are written in order, 4 , 7 , x , y, 11

Mathematics
1 answer:
Len [333]3 years ago
6 0
0 and 5 would be my guess.
0+4+5+7+11= 27
27/5= 25 2/5 which rounds to 25
least to greatest: 0, 4, 5, 7, 11
5 is median because it is in the middle.
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PLEASE HELP!!!!!! the sum of a number times 10 and 15 is at most -17
Brilliant_brown [7]

Let the number = x

Writing the equation you have:

10x + 15 <= -17

Solve for x

Subtract 15 from both sides:

10x <= -32

Divide both sides by 10:

X <= -32/10

Simplify:

X <= -16/5 as a fraction or -3.2 as a decimal

3 0
3 years ago
Find the value of x. Round to the nearest tenth.
Aliun [14]

Answer:

Step-by-step explanation:

Triangle XYZ is a right angle triangle.

From the given right angle triangle

XZ represents the hypotenuse of the right angle triangle.

With ∠34 as the reference angle,

YZ represents the adjacent side of the right angle triangle.

XY represents the opposite side of the right angle triangle.

To determine x, we would apply the Cosine trigonometric ratio

Cos θ = opposite side/hypotenuse. Therefore,

Cos 34 = x/28

x = 28Cos34 = 28 × 0.8290

x = 23.212

To the nearest tenth, it becomes

23.2

7 0
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What is the volume of a sphere with a surface area of 452.39cm^2? Round to the nearest hundredth.
horrorfan [7]
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3 0
3 years ago
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What are the square roots of 1?
Marta_Voda [28]

Answer:

1

Step-by-step explanation:

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3 0
2 years ago
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Solve |p + 2| = 10Solve |p + 2| = 10<br><br> {-12}<br> {-8, 8}<br> {-12, 8}
valentinak56 [21]

By definition, we have

|p+2| = \begin{cases} p+2 &\text{ if } p+2 \geq 0 \\-p-2 &\text{ if } p+2 < 0 \end{cases}

So, we have to solve two different equations, depending of the possible range for the variable. We have to remember about these ranges when we decide to accept or discard the solutions:

Suppose that p+2\geq 0 \iff p \geq -2

In this case, the absolute value doesn't do anything: the equation is

p+2 = 10 \iff p = 10-2 = 8

We are supposing p \geq -2, so we can accept this solution.

Now, suppose that p+2 < 0 \iff p < -2. Now the sign of the expression is flipped by the absolute value, and the equation becomes

-p-2 = 10 \iff -p = 12 \iff p = -12

Again, the solution is coherent with the assumption, so we can accept this value as well.

3 0
3 years ago
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