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zubka84 [21]
3 years ago
13

why is there no need to go further than the multiples of 7 when checking if a number less than 100 is prime​

Mathematics
1 answer:
andrezito [222]3 years ago
5 0

Step-by-step explanation:

because 7 is the highest prime number that when squared is less than 100, 11 yhe next prime number when squared is 121. As such all non-prime numbers less than 100 will be a would have prime factors of either 2, 3, 5 & 7

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4 0
3 years ago
1) f(x) = 2x + 4, g(x) = 4x2 + 1; Find (g ∘ f)(0).
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Answer:

<h2>(g \: \circ \: f)(0) = 17</h2>

Step-by-step explanation:

f(x) = 2x + 4

g(x) = 4x² + 1

In order to find (g ∘ f)(0) we must first find

(g ° f )(x)

To find (g ° f )(x) substitute f(x) into g(x) that's for every x in g(x) replace it with f(x)

That's

<h3>(g \: \circ \: f)(x) = 4( ({2x + 4})^{2} ) + 1 \\  = 4(4 {x}^{2}  + 16x + 16) + 1 \\  =  {16x}^{2}  + 64x + 16 + 1</h3>

We have

<h3>(g \: \circ \: f)(x) =  {16x}^{2}  + 64x + 17 \\</h3>

Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)

We have

<h3>(g \: \circ \: f)(0) = 16( {0})^{2}  + 64(0) + 17 \\</h3>

We have the final answer as

<h3>(g \: \circ \: f)(0) = 17</h3>

Hope this helps you

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Answer:c. F(2)=g(-2)

Step-by-step explanation:

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