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Illusion [34]
3 years ago
6

the length of a rectangle is 4 less than twice the width. the perimeter of the rectangle is 34 feet. find the length and width o

f the rectangle.
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
7 0

Answer: The length is 10ft, the width is 7ft.


Step-by-step explanation:

Let L be the length

Let w be the width

The equation for the perimeter is:

2L+2w=34

We also know that L=2w-4

So we can insert L=2w-4 into 2L+2w=34

2(2w-4)+2w=34

4w-8+2w=34

6w=42

w=7

If the width is 7, we can insert it into 2L+2w=34 to find out the length

2L+14=34

2L=20

L=10

The width is 7 ft, the length is 10 ft.

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Suppose that one-way commute times in a particular city are normally distributed with a mean of 15.43 minutes and a standard dev
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Answer:

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Step-by-step explanation:

A probability is said to be unusual if it is lower than 5% of higher than 95%.

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Problems of normally distributed samples are solved using the z-score formula.

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Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 15.43, \sigma = 2.142

Would it be unusual for a commute time to be between 10 and 11.8 minutes?

The first step to solve this problem is finding the probability that the commute time is between 10 and 11.8 minutes. This is the pvalue of Z when X = 11.8 subtracted by the pvalue of Z when X = 10. So

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This probability is lower than 4%, which means that yes, it would be unusual for a commute time to be between 10 and 11.8 minutes.

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