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BabaBlast [244]
3 years ago
10

Enrique borrowed $23,000 to buy a new car . He pays his uncle 2% interest on the $4,500 he borrowed from him, and he pays the ba

nk 11.5% interest on the rest. What average interest rate does he pay on the total $23,000?
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
5 0

Answer:

The average interest rate will be approximately 9.64%

Step-by-step explanation:

Enrique borrowed $23000

2% interest on $4500 will be

4500 × 2/100

= 45 × 2

= $90

On the rest, which is

$23000 - $4500 = $18500

11.5% interest on $18500 will be

18500 × 11.5/100

= 185 × 11.5

= $2127.50

The total interest will be

$90 + 2127.50 = $2217.50

The average interest will be Total interest multiply by 100, divide by principal

That is Interest = pr/100, where t = 1

r = (I × 100)/p

r = (2217.50 × 100)/23000

r = 221750/23000

r ≈ 9.64%

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Answer:

(0.084,0.396)

Step-by-step explanation:

The 99% confidence interval for the proportion of customers who use debit card monthly can be constructed as

p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }

p=\frac{x}{n}

p=\frac{12}{50}

p=0.24

q=1-p=1-0.24=0.76

\frac{\alpha }{2} =\frac{\0.01 }{2}=0.005

p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }

0.24-z_{0.005} \sqrt{\frac{0.24*0.76}{50} }

0.24-2.58(0.0604)

0.24-0.155832

By rounding to three decimal places we get,

0.084

The 99% confidence interval for the proportion of customers who use debit card monthly is (0.084,0.396).

3 0
3 years ago
Please help, I rally need ir
Mnenie [13.5K]

Answer:

The one on the top at you’re right

3 0
3 years ago
Round 98,471 to the nearest ten thousands
d1i1m1o1n [39]
The answer to this question is 98000
4 0
3 years ago
How do you subtract when there are zero's at the end? For ex. 1000-325 how'd you borrow from 1000?
Alexandra [31]
675. Just subtract. 1000
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Set it up like this.
4 0
3 years ago
Read 2 more answers
Can I get help again w Khan Academy:(
grin007 [14]

Answer:

49

Step-by-step explanation:

x=180-131=49

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2 years ago
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