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oee [108]
3 years ago
10

Can someone help me please asap

Mathematics
1 answer:
irina1246 [14]3 years ago
3 0

Answer:

the slope is 1/3

the y-intercept is at (0,3)

y = 1/3×x + 3

Step-by-step explanation:

a line has the equation

y = a×x + b

the 2 points we were given as being in the line allow us to define now 2 equations to solve for the 2 variables a and b :

3 = a×0 + b => b = 3

2 = a×-3 + b

=> 2 = a×-3 + 3

-1 = a×-3

1 = a×3

a = 1/3

so, our equation is

y = 1/3×x + 3

the slope or incline of the line is expressed by the y/x ratio or simply a, the factor of x. and that is 1/3.

it is positive, as the line goes up (looking from left to right).

and it means that the value of x has to increase by 3 units, so that y increases by 1 unit.

the y-intercept is the point with x=0. so, that is the already predefined point (0,3).

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Answer:

1/1001 < 4/10 < 49/100 < 357/10

Step-by-step explanation:

4/10 => 0.4

49/100 => 0.49

357/10 => 35.7

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A= [2, 3; 2, 1], B=[3; 5]. Find AB &amp; BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

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We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

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Step-by-step explanation:

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