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3 years ago

Factorise fully 3x+18

Mathematics

1 answer:

Nana76 [90]3 years ago

5 0

Find the Greatest Common Factor (GCF)

GCF = 3

Factor out the GCF. (Write the GCF first, and then in parenthesis, divide each term by the GCF)

3(3x/3 + 18/3)

Simplify each term in parenthesis

= 3(x + 6)

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An easier question all wrong or unhelpful or no-work answers will be reported.

ipn [44]

Elimination:

3x - 9y = 3
6x - 3y = -24

3x - 9y = 3
18x - 9y = -72
(subtract)
-15x = 75
÷ -15
x = -5

(3 × -5) - 9y = 3
-15 - 9y = 3
+ 15
-9y = 18
÷ -9
y = -2

Substitution:

6x - 3y = -24
+ 3y
6x = -24 + 3y

÷ 6
x = 4 + 0.5y

3(4 + 0.5y) - 9y = 3
12 + 1.5y - 9y = 3
12 - 7.5y = 3
- 12
-7.5y = -9
÷ -7.5
y = 1.2

x = 4 + (0.5 × 1.2)
x = 4 + 0.6
x = 4.6

So this one didn't fail as much, but I got different numbers. If you have to give in values, I'd give in the values from the elimination because I don't trust myself when it comes to the substitution

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3 years ago

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Step-by-step explanation:

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Colt1911 [192]

Answer:

C. 17.6

General Formulas and Concepts:

Math

Rounding

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

Step 1: Identify Variables

Angle θ = 40°

Opposite Leg = x

Adjacent Leg = 21

Step 2: Solve for x

Substitute in variables [tangent]: $\displaystyle tan(40^\circ) = \frac{x}{21}$
[Multiplication Property of Equality] Isolate x: $\displaystyle 21tan(40^\circ) = x$
Rewrite: $\displaystyle x = 21tan(40^\circ)$
Evaluate: $\displaystyle x = 17.6211$
Round: $\displaystyle x \approx 17.6$

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Factorise fully 3x+18​

Factorise fully 3x+18