$Use\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\y=x^2+6x+10=x^2+2(x)(3)+10=\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2+10\\\\=(x+3)^2-9+10=(x+3)^2+1\\\\Answer:\ \boxed{y=(x+3)^2+1}$

3 0

3 years ago

How to borrow if you can't subtract from the lowest number on top

Elis [28]

Go to the number next to the one you cannot subtract from, take one away, and add a one in front of the number you cannot subtract from. e.g.
27 1(1)7 the answer would be 9
-8 -8

for your problem the answer would be 1109

6 0

2 years ago

Read 2 more answers

Question 11: please help. I will give brainliest to correct answer.

harkovskaia [24]

Answer:

Step-by-step explanation:

8 0

3 years ago

What is a21 of the arithmetic sequence for which a7=−19 and a10=−28? A. -35 B. 35 C. -58 D. -61

shepuryov [24]

Answer: