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3 years ago

GUYS PLEASE HELP ME ILL MARK BRIANLIEST AND GIVE EXTRA POINTS I NEED IT ASAP

Mathematics

1 answer:

matrenka [14]3 years ago

6 0

$n > \frac{81}{2}$

Q2 <em>D</em>

sry I don't hv time to ans more

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Kaitalin earns 6.50$ for each hour she works.on Friday she worked for 3 hours.she also worked on Saturday. If she earned a total

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5 hours

Step-by-step explanation:

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3 years ago

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Can someone help me with this problem.

Oksanka [162]

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negative because the container is losing liquid.

Step-by-step explanation:

y-5x is the rate

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3 years ago

Cindy has 2 boxes of pencils. Patrice has 5 boxes of pencils. Each box has the same number of pencils in it.

Murljashka [212]

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hey mate..

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3 years ago

A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi

Margaret [11]

Answer:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=26Kg$

Step-by-step explanation:

Data

Brine a (Ba)

$V_{Ba}=5\frac{Lt}{min}\\ Concentration(Bca)=0.05\frac{Kg}{Lt}$

Brine b (Bb)

$V_{Bb}=10\frac{Lt}{min}\\ Concentration(Bcb)=0.04\frac{Kg}{Lt}$

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: $y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}$

Finally:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=0.65\frac{Kg}{min}(40min)=26Kg$

being y(t) the amount of salt (y) per unit of time (t)

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3 years ago

Consider the quadratic function Y= -(x-3)^2+4

wlad13 [49]

Answer:

-(x^2-2*x*3+3^2)+4=-x^2+6x-9+4=x^2+6x-5

Step-by-step explanation:

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3 years ago