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AVprozaik [17]
3 years ago
9

According to the 2000 Census the population of Canton was 7,720. Holly Spring's population was 3,200. Canton's population increa

ses at a rate of 80 people a year and Holly Spring's population increases by 120 people a year. Which equation may be used to determine the number of years before the populations are equal?
Mathematics
2 answers:
Kazeer [188]3 years ago
8 0
Firstly, the rate of increase of Canton = 80/7720 = 0.010
The rate of increase of HP = 120/3200 = 0.0375
Apply  the formula of compound interest==> A =A'(1+i)^n
The population will be equal when the following equality is satisfied

7720(1+0.01)^n = 3200(1+0.0375)^n

or

7720x1.01^n = 3200x1.0375^n

Divide both sides by 3200 ===>(193/80)x1.01^n=1.0375^n
Mariana [72]3 years ago
7 0

Answer:

the answer would be  D) 7720 + 80x = 3200 + 120x

Step-by-step explanation:

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Let's do this by Briot-Ruffini


First: Find the monomial root


x - 2 = 0

x = 2


Second: Allign this root with all the other coeficients from equation

Equation = -3x³ - 2x² - x - 2

Coeficients = -3, -2, -1, -2

2 | -3 -2 -1 -2


Copy the first coeficient


2 | -3 -2 -1 -2

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Multiply him by the root and sum with the next coeficient


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2 | -3 -2 -1 -2

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Do the same


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2 | -3 -2 -1 -2

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The same,


2.(-17) = -34

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2 | -3 -2 -1 -2

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Now you just need to put the "x" after all these numbers with one exponent less, see


2 | -3x³ - 2x² - 1x - 2

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You may be asking what exponent -36 should be, and I say:


None or the monomial. He's like the rest of this division, so you can say:


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(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)


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