I think y=2 there both on the 2 y intercept straight from each Other
We are trying to find the <em>Least Common Multiple</em>. This is a number that both 4 and 8 can be multiplied by a whole number to achieve, more specifically, the minimum of that list of numbers. This one is really simple. Since 8 is a multiple of 4 (4 x 2 = 8), the LCM is 8! (8 is also a multiple of 8 because 8 x 1 = 8).
<u>So the answer is 8.</u>
Answer:
n = m r - r t
Step-by-step explanation:
Solve for n:
m = n/r + t
Hint: | Reverse the equality in m = n/r + t in order to isolate n to the left hand side.
m = n/r + t is equivalent to n/r + t = m:
n/r + t = m
Hint: | Isolate terms with n to the left hand side.
Subtract t from both sides:
n/r = -t + m
Hint: | Solve for n.
Multiply both sides by r:
Answer: n = m r - r t
I’m not sure if it’s a.) f(x)=(x-5)2+2 because it’s vertex is (5,2) although it doesn’t pass through (6,3). It passes through (6,4)
I think the answer is c.) none of these
Here’s the graph for it
58.1 since 4 is not greater than 5 so it cant be rounder up to 2