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ANTONII [103]
3 years ago
8

My homework asks to evaluate this: 8-11 Times the square root of 25 over 121

Mathematics
1 answer:
navik [9.2K]3 years ago
4 0
8 - 11 = -3. The square root of 25/121 =  (the square root of 25) / (the square root of 121) = 5/11 .   -3 x 5/11 = -3/1 x 5/11 = (-3 x 5) / (1 x 11) = (-15)/11 = -15/11.
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N – 3 = -1 please solve this!!
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Answer:

N = 2

Step-by-step explanation:

n - 3 = -1         Original

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n = 2                Simplify

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marta [7]

Answer:

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Step-by-step explanation:

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By inspection we just list some multiples of 9:

9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99

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20, 40, 60, 80, 100, 120

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For the Euclidean algorithm, we should divide the greatest of the two numbers, by the smallest one, and keep track of the remainder:

20 = 9 * 2 + 2

Then we divide 9 by the remainder we got, which is 2:

9 =  2 * 4 + 1

we would continue doing this until getting a remainder of 1 (which we just did). Finally we "solve" for 1, from the last equation:

9 - 2*4 = 1

And then we solve for 2 from the first equation, and plug that in into the previous equation:

20 - 9*2 =2

9 - ( 20 - 9*2)*4 = 1

which does give us the same solution: 9\cdot 9 +20\cdot (-4)=1

5 0
4 years ago
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