3 years ago

My homework asks to evaluate this: 8-11 Times the square root of 25 over 121

1 answer:

4 0

8 - 11 = -3. The square root of 25/121 = (the square root of 25) / (the square root of 121) = 5/11 . -3 x 5/11 = -3/1 x 5/11 = (-3 x 5) / (1 x 11) = (-15)/11 = -15/11.

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ivanzaharov [21]

$\Large \mathbb{SOLUTION:}$

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