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3 years ago

What is 16.748 rounded to nearest hundredths

Mathematics

1 answer:

IrinaK [193]3 years ago

7 0

Answer:

17.000

Step-by-step explanation:

You round up because 7 is closest to 10

Hope this helps :)

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During a three-day period, the stock of Money, Inc. gained 6 points, lost 10 points, and gained 2 points. What was the total cha

hjlf

It didn’t have no gaining

4 0

3 years ago

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Solve for points....

Ivan

Answer:

Step-by-step explanation:

For Mr Rowley,

Ratio of Number of home works to the number of exit tickets = $\frac{12}{14}$

= $\frac{6}{7}$

= 6:7

For Ms Rivera,

Ratio of Number of home works to the number of exit tickets = $\frac{36}{42}$

= $\frac{6}{7}$

= 6:7

Since, both the ratios are same, fractions will be proportional.

$\frac{12}{14}=\frac{36}{42}$

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3 years ago

120 - 40 divided by 4 x 6 write 2 steps and then answer and i will give u brainliest

astra-53 [7]

Answer:

your answer is 10/3 (fraction)

Step-by-step explanation:

120-40=80

4 x 6=24

80/24=

first divide both sides by four and get 20/6
then divide by 2 to get 10/3 (fraction form)

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3 years ago

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Find the slope of the lines. Are the 2 lines parallel or perpendicular? Explain how you can use the slope of two lines to tell i

rewona [7]

Answer:

slope = $\frac{3}{7}$ and - $\frac{7}{3}$ , perpendicular

Step-by-step explanation:

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = $\frac{3}{7}$ x + 11 is in this form with m = $\frac{3}{7}$

Rearrange 7x + 3y = 13 into this form

subtract 7x from both sides

3y = - 7x + 13 ( divide all terms by 3 )

y = - $\frac{7}{3}$ x + $\frac{13}{3}$ ← in slope- intercept form

with m = - $\frac{7}{3}$

• Parallel lines have equal slopes

• The product of perpendicular slopes = - 1

The lines are not parallel since slopes are not equal

$\frac{3}{7}$ × - $\frac{7}{3}$ = - 1

Hence lines are perpendicular

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3 years ago

2x+y=3, 5x-2y=12 how to solve this

Leviafan [203]

Start by getting one of the equations in terms of one variable, in this case lets put the first equation in terms of y

2x+y=3 ---> y=3-2x

now we plug that into the second equation

5x-2y=12 ---> 5x-2(3-2x)=12

we can then multiply and simplify

5x-2(3-2x)=12 ---> 5x-6+4x=12 ---> 9x-6=12 ---> 9x=18 ---> x=2

we can now plug x=2 into an equation to solve for y

2(2)+y=3 ---> 4+y=3 ---> y=-1

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3 years ago

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