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3 years ago

What is 16.748 rounded to nearest hundredths

Mathematics

1 answer:

IrinaK [193]3 years ago

7 0

Answer:

17.000

Step-by-step explanation:

You round up because 7 is closest to 10

Hope this helps :)

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−1/5a+9/5a+6 =30 solve for a

Nonamiya [84]

Answer:

a=15

Step-by-step explanation:

Solve for a by simplifying both sides of the equation, then isolating the variable.

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3 years ago

Which is the image of ABC for a 90° counterclockwise rotation about P?

timofeeve [1]

The answer is EFD because the turn is counterclockwise, around point P

- Your welcome

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3 years ago

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Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

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3 years ago

Simplify.

yKpoI14uk [10]

$(-5p^4z^6u)^3$

$= (-5)^3p^{4 \times 3}z^{6 \times 3} u^3$

$= -125p^{12}z^{18} u^3$

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$\text {Answer = } -125p^{12}z^{18} u^3 \text { (Answer C) }$
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Artyom0805 [142]

Answer:

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Step-by-step explanation:

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3 years ago

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