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3 years ago

By selling a watch in Rs 150 and Rs 200 loss and profit are happened

Mathematics

1 answer:

Travka [436]3 years ago

3 0

Answer:

Rs 175

Step-by-step explanation:

Suppose the cost is x and at Rs150 the loss is 150-x (this should be a negative number).

At Rs200, the profit is 200-x.

So we have an equation: minus 150 minus x is equal to 200 minus x.

To solve the equation, the cost price X is Rs175.

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Simplify foundation of alegebra

Eva8 [605]

1.) -8 + 10(6 + 4r)

First multiply the 10 into (6 + 4r)

-8 + 60 + 40r

52 + 40r

2.) (8m² - 8m + 8) - (2m - 7m² - 6)

Distribute the - into (2m - 7m² - 6)

8m² - 8m + 8 - 2m + 7m² + 6

Combine like terms

15m² - 10m + 14

(idk if you need to factor this or if you can leave it as is)

3 0

3 years ago

Pete and his sister, Sophie, play the game Space Mission Commander on their video game console. Pete has already completed 27 mi

kondor19780726 [428]

Step-by-step explanation:

Pete has already completed 27 missions. Pete plans to complete 3 missions per week

Let x represents weeks

Games completed = 3x + 27

Sophie has only completed 13 missions. Sophie plans to complete 5 missions per week.

Games completed = 5x + 13

3x + 27 = 5x + 13

27 - 13 = 5x - 3x

2x = 14

x = 7

By the seventh week, they would have completed equal number of games,

6 0

2 years ago

Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of

alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

- The standard form of the linear equation is Ax + BC = C, where

A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

parallel bases and which of them are the non-parallel bases

# The side RS

∵ $m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}$

# The side ST

∵ $m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}$

# The side TU

∵ $m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}$

# The side UR

∵ $m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}$

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

∵ The midpoint of RS = $(\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})$

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

midpoint of RS

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0

3 years ago

There are 30 computers in the media lab there are 4 activity booklets for every 2 computers in the media lab.

AURORKA [14]

Answer:

There are 60 activity booklets in the media lab.

Step-by-step explanation:

- 30/2 = 15

Why divide those numbers?

For every 2 computers in a lab with 30 computers means you have to divide

- 15x4 = 60

Why multiply those numbers?

4 activity booklets for every 2 computers in a lab of 30 computers, so multiply

I hope this helps.

7 0

3 years ago

The mode interval in a histogram is the interval that has the highest frequency.

raketka [301]

This is true.

When we're talking about the mode, we're usually talking about the number which has the highest frequency in a given set of numbers. For example, out of the numbers:

1 2 3 4 5 6 5 4 5 5 5

5 will be the mode.

4 0

3 years ago