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3 years ago

What is log6 8+ log6 27

Mathematics

2 answers:

defon3 years ago

7 0

$\log_6 8 + \log_6 27=\log_6 (8 \times 27)=\log_6 216=3$

ikadub [295]3 years ago

3 0

Log8 base 6 + Log27 base 6.

When you have a plus, you multiply. That is the law of logarithm.

= Log (8 * 27) base 6.

= Log 216 base 6.

= Log (6^3) base 6.

= 3* Log 6 base 6. Law of logarithm. Log of a number to same number of base = 1.

= 3 * 1 = 3.

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Find g[h(x)] if g(x)=x^2 and h(x)=x+3

svetlana [45]

Answer:

g(h(x)) = [x + 3]^2 or x^2 + 6x + 9

Step-by-step explanation:

g[h(x)] signifies that h(x) is the input to g(x).

Writing out g(x) = x^2 and replacing "x" with [x + 3], we get:

g(h(x)) = [x + 3]^2 or x^2 + 6x + 9

8 0

3 years ago

Using the formula for initial velocity h=-16t2+VT the height of any object can be found by the time, Annalee serves a volleyball

Marrrta [24]

The ball will hit the ground at 0.125 seconds

<h3>Quadratic function</h3>

The equation of the function is a quadratic function, and the function is given as:

$h = -16t^2 + 2t$

When the ball hits the ground, the value of h is 0.

So, the equation of the function becomes

$-16t^2 + 2t = 0$

Subtract 2t from both sides of the equation

$-16t^2 =- 2t$

Divide both sides by -2t

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Divide both sides by 8

$t =0.125$

Hence, the ball will hit the ground at 0.125 seconds

Read more about quadratic functions at:

brainly.com/question/11631534

5 0

3 years ago

Find the supplement of 29°

Nonamiya [84]

Answer:

151°

Step-by-step explanation:

Supplementary angles equal 180°, so all you have to do here is subtract 29 from 180 to get 151° as the supplement.

4 0

3 years ago

3 + (-3)^2 - (9 +7)^0

MatroZZZ [7]

Answer:

Step-by-step explanation:

3+(−3)^2−(9+7)^0

=3+9−(9+7)^0

=12−(9+7)^0

=12−16^0

=12−1

=11

any number to the power of 0 is ALWAYS 1

3 0

3 years ago

Read 2 more answers

For the function, f(x)=(9x+7)/(2x+4)

AVprozaik [17]

A. $f(x)=\frac{9x+7}{2x+4}\\f'(x)=\frac{(9)(2x+4)-(9x+7)(2)}{(2x+4)^2}\\f'(x)=\frac{(18x+36)-(18x+14)}{(2x+4)(2x+4)}\\f'(x)=\frac{22}{4x^2+16x+16}\\f'(x)=\frac{11}{2x^2+8x+8}\\\frac{11}{(2x+4)(x+2)}=0\\\frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty$ - There are no critical points because the graph is neither continuous nor smooth. There is a discontinuity at x = 2.

B. $\frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty$ - The absolute maximum is f(lim⇒-2_-) = infinity. The absolute minimum is f(lim⇒-2_+) = -infinity. This applies to the interval [-10, 7].

C. $f(x)=\frac{9x+7}{2x+4}\\f(0)=\frac{9(0)+7}{2(0)+4}\\f(0)=\frac{7}{4}\\f(0)=1.75\\f(5)=\frac{9(5)+7}{2(5)+4}\\f(5)=\frac{45+7}{10+4}\\f(5)=\frac{52}{14}\\f(5)=\frac{26}{7}\\f(5)=3.714$ - The absolute maximum is f(5) = 26/7 or 3.714. The absolute mimimum is f(0) = 1.75. This applies to the interval [0, 5]. Proof: graph f(x) at [0, 5] on a graph or graphing calculator.

5 0

3 years ago