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lina2011 [118]
3 years ago
15

Using the formula for initial velocity h=-16t2+VT the height of any object can be found by the time, Annalee serves a volleyball

with a initial velocity of 30 feet per second, how long will it take to hit the ground
Mathematics
1 answer:
Marrrta [24]3 years ago
5 0

The ball will hit the ground at 0.125 seconds

<h3>Quadratic function</h3>

The equation of the function is a quadratic function, and the function is given as:

h = -16t^2 + 2t

When the ball hits the ground, the value of h is 0.

So, the equation of the function becomes

-16t^2 + 2t = 0

Subtract 2t from both sides of the equation

-16t^2 =- 2t

Divide both sides by -2t

8t =1

Divide both sides by 8

t =0.125

Hence, the ball will hit the ground at 0.125 seconds

Read more about quadratic functions at:

brainly.com/question/11631534

You might be interested in
Is 3(x + 1)2 = (3x + 3)2 an identity? Explain and show your reasoning.
Scilla [17]

Answer:

YES

Step-by-step explanation:

The equation, 3(x + 1)2 = (3x + 3)2, would be an identity if the equation remains true regardless of the value of x we choose to plug in into the equation.

Let's find out if we would always get a true statement using different value of x.

✍️Substituting x = 1 into the equation:

3(x + 1)2 = (3x + 3)2

3(1 + 1)2 = (3(1) + 3)2

3(2)2 = (3 + 3)2

12 = 12 (TRUE)

✍️Substituting x = 2 into the equation:

3(x + 1)2 = (3x + 3)2

3(2 + 1)2 = (3(2) + 3)2

3(3)2 = (6 + 3)2

18 = 18 (TRUE)

✍️Substituting x = 3 into the equation:

3(x + 1)2 = (3x + 3)2

3(3 + 1)2 = (3(3) + 3)2

3(4)2 = (9 + 3)2

24 = 24 (TRUE)

Therefore, we can conclude that the equation, 3(x + 1)2 = (3x + 3)2, is an identity.

8 0
3 years ago
Which is the answer and how did you solve it?
motikmotik
Its pretty simple

9x-7y = 22
x + 3y = -24

(9x-7y = 22)
-9(x + 3y = -24)
= -9x -27y = 216
+ 9x-7y = 22
= -34y = 238
= / -34 = 238/-34
y = -7

now plug -7 in one of the equation
x + 3(-7) = -24
x -21 = -24
+21. +21
x = -3

so answer is x = -3 and y = -7

3 0
3 years ago
Given: KLMN is a trapezoid m∠K = 90°, m∠N = 45° LK = LM = 10 Find: KN, Area of KLMN
Ilya [14]
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to A= \frac{LM+KN}{2} *MP= \frac{10+20}{2} *10=150 sq. units.


5 0
3 years ago
How can you tell whether the parabola had a reflection?
DIA [1.3K]
When it doesn’t look like a U anymore and is upside down
Looking at an equation than when x is negative
3 0
3 years ago
Help, I need #2,3, and 4.
vredina [299]
I can’t read it , it’s very blurry .





try reuploading.
6 0
3 years ago
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