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3 years ago

Which of these is an optional/voluntary deduction?

Mathematics

1 answer:

11111nata11111 [884]3 years ago

3 0

Your answer is healthcare insurance

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What is the multiplicative inverse of 7/5 ? pls no links

Bumek [7]

Answer:

$\frac{5}{7}$

Step-by-step explanation:

The multiplicative inverse of a number n is $\frac{1}{n}$ , then

inverse of $\frac{7}{5}$ is $\frac{1}{\frac{7}{5} }$ = $\frac{5}{7}$

7 0

2 years ago

Read 2 more answers

Solve 2y - 5 over 3 = 4y - 1 over 2

ololo11 [35]

$\frac{2y - 5}{3} = \frac{4y - 1}{2}$
$3(4y - 1) = 2(2y - 5)$
$3(4y) - 3(1) = 2(2y) - 2(5)$
$12y - 3 = 4y - 10$
$8y - 3 = -10$
$8y = -7$
$\frac{8y}{8} = \frac{-7}{8}$
$y = -0.875$

4 0

3 years ago

What is the percentage of those who try in one year to quit smoking cigarettes on their own actually succeed

Serjik [45]

The percent of people of smoke cigarettes is 20.9%..

4 0

3 years ago

What is the type of correlation for the plot?

pychu [463]

Answer:
It is a No Correlation plot! There is no relationship between variables.

5 0

3 years ago

Find the value of x<br><br>urgent!! plz help me! will give the brainliest

Anarel [89]

Answer:

x = 2

Step-by-step explanation:

$\frac{1}{2} (x - 1) - \frac{1}{6} (x+1) = 0$

In an equation our aim is to find the value of what we are looking for as well as keeping the equation balanced. For example if we divided by 2 only from one side then the equation would change so it's an important rule to keep in mind when solving equations, that you need to keep both sides of the equation the same.

$\frac{1}{2} (x - 1) - \frac{1}{6} (x+1) = 0$

→ Expand the brackets

$\frac{1}{2} x- \frac{1}{2}-\frac{1}{6}x -\frac{1}{6} =0$

→ Multiply everything by 12 to make solving the equation easier

6x - 6 - 2x - 2 = 0

→ Simplify equation

4x - 8 = 0

→ Add 8 to both sides to isolate 4x

4x = 8

→ Divide by 4 on both sides to isolate x

x = 2

⇒ We can substitute x = 2 back into the equation to see if the solution is correct, if we get 0 on both sides then x = 2 is correct

$\frac{1}{2} (x - 1) - \frac{1}{6} (x+1) = 0$

⇒ Substitute in the values

$\frac{1}{2} (2-1)-\frac{1}{6} (2+1) = 0$

⇒ Simplify

$\frac{1}{2} (1)-\frac{1}{6} (3) = 0$

⇒ Simplify further

$\frac{1}{2} -\frac{1}{2} =0$

0 = 0

The solution x = 2 is correct

4 0

3 years ago