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nekit [7.7K]
3 years ago
11

The surface area of the top surface of the water in a circular swimming pool is about 188 square feet. Estimate the radius of th

e pool, to the nearest foot. about 8 feet about 14 feet about 12 feet about 10 feet
Mathematics
2 answers:
Scorpion4ik [409]3 years ago
5 0

Your answer would be 14ft.

Just square root 206, then round to the nearest whole number.

Vera_Pavlovna [14]3 years ago
4 0
It's about 206 square feet
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HELP ME ASAP!!!!!!!!
Marina CMI [18]

Answer:

Step-by-step explanation:

1) 30 : 100 = x : 299

x = (30 x 299)/100

x = 89,70 $

2) 299 - 89,70 = 209,30 $

3)  5 : 100 = x : 209,30

x = 10,465 $

209,30 + 10,465 = 219,77 $

5 0
3 years ago
Answer plsss........ ​
Alex Ar [27]

1. x+12

2. x-8

3. 3*x

4. x^(2)+5

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6. 4*(x+6)

7. (1/2)*x

8. 2x+8

9. x^(2)+3

10. (x/3)+12

Additional activity

1. 2-50

2.20/4=5

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4.three times two then add to four equals ten

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7 0
3 years ago
I WILL GIVE BRAINLIEST Part A: Create a fifth-degree polynomial with four terms in standard form. How do you know it is in stand
qwelly [4]

5x 3y^3 2z

I know it is in standard form because there are no more like terms.

Part B: Polynomials are always closed under multiplication. Unlike with addition and subtraction, both the coefficients and exponents can change. The variables and coefficients will automatically fit in a polynomial. When there are exponents in a multiplication problem, they are added, so they will also fit in a polynomial.

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7 0
2 years ago
A car travels at a constant speed.
ad-work [718]

Answer:

see below

Step-by-step explanation:

<h3>Given</h3>
  • Distance is 142.2 m, correct to 1 decimal place
  • Time is 7 seconds,  correct to nearest second
<h3>To find:</h3>
  • Upper bound for the speed
<h3>Solution </h3>

<em>Upper bound for the speed  = upper bound for distance/lower bound for time</em>

  • Upper bound for distance = 142.25 m  (added 0.1/5 = 0.05)
  • Lower bound for time = 6.5 seconds  (subtracted 1/2 = 0.5)

<u>Then, the speed is:</u>

  • 142.25/6.5 = 21.88 m/s
  • 21.88 = 21.9 m/s correct to 1 decimal place
  • 21.88 = 22 m/s correct to nearest m/s

4 0
3 years ago
the line containing the altitude to the hypotenuse of a right triangle whose vertices are p(-1, 1), q(3, 5), and r(5, -5).
finlep [7]

The equation of the straight line is given by 5y-x=6

An equation can be used to describe a straight line drawn on the Cartesian Plane. These equations have a generic structure and can change based on the slope and where the line intersects the axes.

We will greatly simplify this issue by utilizing the fact that this triangle is specified as a right triangle. We would have had to establish the presence of a right angle if it had been presented as a general triangle.

The segment QR is the hypotenuse of the triangle.

Any side's altitude is located along a line that is perpendicular to that side. We are aware that the slopes of perpendicular lines are negative reciprocals, or:

Slope of line joining  Q(3, 5) and R(5, -5)

m=\frac{y_2-y_1}{x_2-x_1}

Hence slope is= -10/2= -5

Now we know that for two perpendicular line the slope of one line is the negative reciprocal of the other.

Slope of line perpendicular to QR=1/5

This line passes through P(-1,1)

Equation of the straight line that passes through (1,-1) and with a slope of 1/5 is given by:

(y-y_1)=m(x-x_1)\\

Substituting the values we get:

y-1=1/5(x+1)

or,5y-5=x+1

or,5y-x=6

Hence the equation of the required line is : 5y-x=6

To learn more about straight lines visit:

brainly.com/question/17757770

#SPJ4

8 0
2 years ago
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