The perimeter of the large triangle = 2 * perimeter of the small one so:-
2x + 4x + 2(4x + 1) = 62
14x = 60
x = 4 2/7 answer
Answer:
Step-by-step explanation:
The probability is
P
(
A
)
=
1
3
Explanation:
To calculate the probability you have to count the number of all possible results
|
Ω
|
and the number of results that fulfill the given condition
|
A
|
.
In this case
Ω
=
{
1
,
2
,
3
,
4
,
5
,
6
}
Thereare 6 possible result of a dice toss. So
|
Ω
|
=
6
The given condition is "the result is divisible by
3
", so
A
=
{
3
,
6
}
- those are the only numbers divisible by
3
, so
|
A
|
=
2
.
Finally to calculate the probability we have to divide
|
A
|
by
|
Ω
|
.
P
(
A
)
=
|
A
|
|
Ω
|
=
2
6
=
1
3
Note The probability is never larger than
1
, so if you get such result then there must be a mistake in calculations.
Answer:
No, the on-time rate of 74% is not correct.
Solution:
As per the question:
Sample size, n = 60
The proportion of the population, P' = 74% = 0.74
q' = 1 - 0.74 = 0.26
We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.
Now,
The proportion of the given sample, p = 
Therefore, the probability is given by:
![P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]](https://tex.z-dn.net/?f=P%28p%5Cleq%200.634%29%20%3D%20%5B%5Cfrac%7Bp%20-%20P%27%7D%7B%5Csqrt%7B%5Cfrac%7BP%27q%27%7D%7Bn%7D%7D%7D%5D%5Cleq%20%5B%5Cfrac%7B0.634%20-%200.74%7D%7B%5Csqrt%7B%5Cfrac%7B0.74%5Ctimes%200.26%7D%7B60%7D%7D%7D%5D)
P![(p\leq 0.634) = P[z\leq -1.87188]](https://tex.z-dn.net/?f=%28p%5Cleq%200.634%29%20%3D%20P%5Bz%5Cleq%20-1.87188%5D)
P![(p\leq 0.634) = P[z\leq -1.87] = 0.0298](https://tex.z-dn.net/?f=%28p%5Cleq%200.634%29%20%3D%20P%5Bz%5Cleq%20-1.87%5D%20%3D%200.0298)
Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %
Thus the on-time rate of 74% is incorrect.