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Rama09 [41]
3 years ago
7

Find the value of x round to the nearest tenth

Mathematics
1 answer:
sergey [27]3 years ago
8 0
(1/2) of 22 = 11.

x^2 = (11)^2 + (6)^2

x^2 = 121 + 36

x^2 = 157

sqrt{x^2} = sqrt{157}

x = 12.5299640861

x = 12.5

Done!
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7 0
3 years ago
What is the solution to y=-2x+7 and y=5x-7
Alexandra [31]

Answer:

x-2,y= 3, it can also be written as (2 ,3)

Step-by-step explanation:

2x-7y=5x-7-2x-7=5x-75x+2x=

7+77x=14x=2y=5x-7=5*2-7=10-..

4 0
1 year ago
Machine A and machine B both make car parts. Machine A makes 7 parts every 10 minutes. Machine B makes 16 parts every 15 minutes
exis [7]

Answer:

1184

Step-by-step explanation:

Given :

No. of parts made by machine A in 10 minutes = 7

No. of parts made by machine A in 10*6 minutes (1 hour) = 7 * 6 = 42 parts

No. of parts made by machine A in 12 hours as

                                               required in problem = 42 * 12 =  504

______________________________________________________

No. of parts made by machine B in 15 minutes = 17

No. of parts made by machine A in 15*4 =60 minutes (1 hour) = 17 * 4= 68 parts

No. of parts made by machine B in 10 hours as

                                               required in problem = 68 * 10 =  680

______________________________________________________

There fore total no. of parts made by

machine A and machine B  on Monday = 680 + 504 = 1184 (Answer)

6 0
2 years ago
b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
3 years ago
I need help on this question
kherson [118]

Answer:

A

Step-by-step explanation:

Just put x = 80 and y = 210 into the equation...

or put x = 40, y = 90.

A:

210 - 90 = 3(80-40)

120 = 120√

B:

210 + 90 = 3(80+40)

300 = 360×

C:

210 - 90 = 2.6(80-40)

120 = 104×

D:

210 + 90 = 2.6(80+40)

300 = 312×

8 0
3 years ago
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