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timama [110]
3 years ago
8

6x + 4 = 4x – 2 how do I solve this and what are the steps

Mathematics
1 answer:
Lelechka [254]3 years ago
6 0

Answer: -0.6

Step-by-step explanation:

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Write the numbers 1/16, -5/2, -2 1/3, and 16 least to greastest
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Answer:

-2 1/3, -5/2, 1/16, 16

The more negative the number gets, the lesser it would be.

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Convert 0.00001 to the power of 10
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what algorithm (rule) will produce the correct result for the sum "a+b" where a and b each represent any rational number.
Leokris [45]

Answer:

To find the sum of  a + b where a and b are rational number.

1. when a and b are natural numbers

just add them . for example a =3, b=8

then ,a + b = 11

2. When a and b  are whole numbers,

simply add them . for example a= 0, b=8

a+ b = 0 + 8= 8

3. When  a and b are integers

for example, a =-1 b=8,

a+ b= -1+ 8 =7,

a=-2, b= -8

a+ b= -2-8=-10

a= -6 , b=2

a+ b= -6 + 2= -4

a= 8, b= -2

a+ b= 8 +(-2) =6

I have written this because Rational number = [Integers{Whole number(Natural number)}]

now when a= Any fraction=\frac{p}{q} and b = Any fraction=\frac{u}{v}

now ,

\frac{p}{q} + \frac{u}{v}

Find L.C.M of q and v

= if q and v are Co-prime , just multiply them to find their  L.C.M.

For example 14,9. LCM=14×9=126

Otherwise, Find factors of q and v . Then take out common factors first and then multiply the remaining with with common factors.For example

q=12 and v=18

12 =2×2×3

18=2×3×3

common factor =2,3

non common=2,3

L.C.M= 2×2×3×3=36

Suppose LCM of q and v = r

then ,\frac{p}{q} + \frac{u}{v}

=\frac{{\frac{r}{q}}\times p+{\frac{r}{v}\times u}}{r}\\

= {{\frac{r}{q}}\times p+{\frac{r}{v}\times u}} = k

then ,

a + b=\frac{k}{r}





5 0
3 years ago
When making a long distance call from a certain pay phone, the first three minutes of a call cost $2.10. After that, each additi
Sauron [17]

Answer: the number of minutes of long distance call that one can make is lesser than or equal to 12 minutes.

Step-by-step explanation:

Let x represent the number of minutes of long distance call that one makes.

The first three minutes of a call cost $2.10. After that, each additional minute or portion of a minute of that call cost $0.45. This means that if x minutes of long distance call is made, the total cost would be

2.10 + 0.45(x - 3)

Therefore, the inequality to find the number of minutes one can call long distance for $6.15 is expressed as

2.10 + 0.45(x - 3) ≤ 6.15

2.10 + 0.45x - 1.35 ≤ 6.15

0.75 + 0.45x ≤ 6.15

0.45x ≤ 6.15 - 0.75

0.45x ≤ 5.4

x ≤ 5.4/0.45

x ≤ 12

4 0
3 years ago
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