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Bumek [7]
3 years ago
12

Solve F(x) for the given domain. Include all of your work in your final answer. Submit your solution.

Mathematics
2 answers:
amm18123 years ago
5 0
Hello : 
<span>F(x) = x 2 + 2 the domain is : R
F(x - h) = (x - h )² +2 = x² - 2xh +h² +2</span>
Anna71 [15]3 years ago
4 0

Answer:

As per the given statement:

F(x) = x^2+2     for all x belongs to R              ......[1]

Then, find F(x-h);

Substitute x-h in place of x in [1] we get;

F(x-h) = (x-h)^2+2

Using identity rule:

(a-b)^2 = a^2 +b^2 -2ab

Apply this rule we have;

F(x-h) = x^2+h^2-2xh+2

Therefore, final answer is, F(x-h) = x^2+h^2-2xh+2

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Answer as soon as possible
alexandr1967 [171]

Answer:

C −2a^3+9a^2+45a+6ab^2+18b^2

Step-by-step explanation:

(a+3) ( −2a^2+15a+6b^2)

Distribute the a to the large term in parentheses and the 3 to the large term in parentheses

a ( −2a^2+15a+6b^2)+3  ( −2a^2+15a+6b^2)

−2a^3+15a^2+6ab^2 −6a^2+45a+18b^2

Combine like terms

−2a^3+15a^2−6a^2+6ab^2 +45a+18b^2

-2 a^3 + 9 a^2 + 6 a b^2 + 45 a + 18 b^2

3 0
3 years ago
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3x-y=1;d:{-3,-1,0,4}
Maslowich
First, rearrange the equation so that it is solving for y:
3x - y = 1
     +y   +y
3x = y + 1
-1         -1
3x - 1 = y
Now substitute the domain values you have listed into the 'x' of the equation to get the values for y.
For example:
3(-3) - 1 = y
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8 0
3 years ago
There are 15 identical pens in your drawer, nine of which have never been used. On Monday, yourandomly choose 3 pens to take wit
DaniilM [7]

Answer: p = 0.9337

Step-by-step explanation: from the question, we have that

total number of pen (n)= 15

number of pen that has never been used=9

number of pen that has been used = 15 - 9 =6

number of pen choosing on monday = 3

total number of pen choosing on tuesday=3

note that the total number of pen is constant (15) since he returned the pen back .

probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

probability of picking a pen that has been used on tuesday = 6/15 = 2/5

probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5

on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .

we know that

probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.

to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution

p(x=r) = nCr * p^{r} * q^{n-r}

n= total number of pens=15

r = number of pen chosen on tuesday = 3

p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

by slotting in the parameters, we have that

p(x=3) = 15C3 * (\frac{2}{5})^{3} * (\frac{3}{5})^{12}

p(x=3) = 455 * 0.4^{3} * 0.6^{12}

p(x=3) = 455 * 0.064 * 0.002176

p(x=3) = 0.0633

thus probability that 3 of the pens has been used on tuesday. = 0.0633

probability of ball that none of the 3 pen has never being used on tuesday  = 1 - 0.0633 = 0.9337

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50/50 chance to be wrong or right
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