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SVETLANKA909090 [29]
3 years ago
11

Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x?

Mathematics
2 answers:
vovikov84 [41]3 years ago
6 0

Answer:

x=\frac{-3\pm\sqrt{(3)^2-4(5)(-4)}}{2(5)}

Therefore, Option 1 is correct.

Step-by-step explanation:

We have been given the quadratic equation:

5x^2+3x-4=0

If we compare it will general quadratic equation which is: ax^2+bx+c=0

Here, a=5,b=3 and c= -4.

Now, we will use the formula:

And then x=\frac{-b\pm\sqrt{D}}{2a}

Where,D=b^2-4ac

x=\frac{-3\pm\sqrt{(3)^2-4(5)(-4)}}{2(5)}

Therefore, Option 1 is correct.

MrMuchimi3 years ago
4 0

Answer:

Choice a is correct answer.

Step-by-step explanation:

Given equation is :

5x²+3x-4 = 0

we have to solve it by finding the value of x.

ax²+bx+c = 0 is general quadratic equation.

x = ( -b±√b²-4ac) / 2a is quadratic formula which is used to find the value of x in quadratic equation.

Comparing given equation with quadratic equation , we get

a = 5 , b = 3 and c = -4

putting above values in quadratic formula  , we get

x = ( -(3)±√(3)²-4(5)(-4) ) / 2(5)

x = ( -3±√(3)²-4(5)(-4) / 2(5) which is the answer.

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Answer:

d.

Step-by-step explanation:

Left line is defined when x < 1 (x is less than 1). The point is not full and that means that x = 1 is not included.

Right line is defined when x is greater or equal to one x ≥ 1.

Options that have x < 1 and x ≥ 1 are b and d, so the answer is one of those.

Equations of the lines are in slope-intercept form y = mx + b, where m is slope and b is y-intercept.

Right line has steeper slope than left line, so the slope of right line will have bigger absolute value. That is the case with option d. (Left line has slope -1 and right one has slope -2, absolute value of right slope is bigger.)

You could also check with y-intercepts. Left line has y-intercept at y = 2 and left line is defined when x < 1. Only option d meets these conditions.

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