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3 years ago

11

Suppose a triangle with angles measuring 37°, 59°, and 84° is reflected across the y-axis of a coordinate grid. Which would be t

he measure of an angle of the resulting triangle?

1 answer:

stich3 [128]3 years ago

4 0

I'm assuming there are supposed to be choices, but if a figure goes through only a reflection, then the angle measures will not change.

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What is the value of x -6/7=-x/84?

AURORKA [14]

Answer:

x = 72 / 85

Step-by-step explanation:

x -6/7=-x/84

x + x/84 = 6/7

84/84x + 1/84x = (12*6) / (12*7)

85/84x = ( 72 ) / ( 84 )

85/84x = 72 / 84

Multiply left and right from the = sign by 84/85 and you do that so you get a division ON THE LEFT SIDE that equals as 1... See how it works:

84/85 * { 85/84 } * x = 84/85 * { ( 72 ) / ( 84 ) }

{ (84 * 85) / ( 85 * 84) } * x = ( 84 * 72 ) / ( 85 * 84 )

(7140) / ( 7140) * x =. ( 6048 ) / ( 7140)

x = 6048 / 7140

x = 72 / 85

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3 years ago

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D. Expenses for a birthday party are not a fixed expense.

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3 years ago

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3 years ago

Read 2 more answers

assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra

Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......$

where, n = number of trials (samples) taken = 15 adult smartphones

r = number of success = at least 4

p = probability of success which in our question is the % of adults

who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}$

= $1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})$

= <u>0.1773</u>

3 0

3 years ago

About a fifth of the potato crop was ruined by a flood. Another fifth of the undamaged potatoes spoiled while being hauled to ma

Lady bird [3.3K]

The answer would be c. 3/5

8 0

2 years ago