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VikaD [51]
3 years ago
11

Line AC is tangent to circle O at point C What is the measure of OAC?

Mathematics
1 answer:
Nuetrik [128]3 years ago
7 0
AC is a tangent so by definition, it touches the circle at exactly one point (point C) and forms a right angle at the tangency point. So angle ACO is 90 degrees

The remaining angle OAC must be 45 degrees because we need to have all three angles add to 180
45+45+90 = 90+90 = 180

Alternatively you can solve algebraically like so
(angle OAC) + (angle OCA) + (angle COA) = 180
(angle OAC) + (90 degrees) + (45 degrees) = 180
(angle OAC) + 90+45 = 180
(angle OAC) + 135 = 180
(angle OAC) + 135 - 135 = 180 - 135
angle OAC = 45 degrees

Side Note: Triangle OCA is an isosceles right triangle. It is of the template 45-45-90. 
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Answer:

5/3

Step-by-step explanation:

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2 years ago
P=2L +2W;P=32,W=7<br><br> 25<br> 16<br> 12.5<br> 9
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Answer:

L = 9

Step-by-step explanation:

Assuming you are trying to find L

P = 2L + 2W

P = 32

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3 years ago
How would you write the equation with a slope of 2/3 and a y-intercept of (0,-3)?
rosijanka [135]

Answer:

y = (2/3)x - 3

Step-by-step explanation:

Slope-intercept form: y = mx + b

Note that:

y = (x , y)

m = slope

x = (x , y)

b = y-intercept.

The point is given to you. Note that:

(x , y) = (0 , -3) ∴

x = 0

y = -3

The slope = m = 2/3

Plug in the corresponding numbers to the corresponding variable:

y = mx + b

-3 = (2/3)(0) + b

-3 = 0 + b

b = -3

Plug in -3 for b in the equation:

y = mx + b

y = (2/3)x -3

y = (2/3)x - 3 is your equation.

~

5 0
3 years ago
Atile factory earns money by charging a flat fee for delivery and a sales price of $0.25 per tile. One customer paid a
Vesnalui [34]

Answer: the first one is C

the second one is B

5 0
3 years ago
The areas of two similar triangles are 75m2 and 300m2. The length of one of the sides of the second triangles is 9m. What is the
Ymorist [56]

Answer:

4.5 m

Step-by-step explanation:

The area of two similar triangles are 75 m2 and 300 m2. This gives you the scale factor of the triangles:

\dfrac{A_{small}}{A_{large}}=k^2\Rightarrow k^2 =\dfrac{75}{300}=\dfrac{3}{12}=\dfrac{1}{4}\Rightarrow k=\dfrac{1}{2}.

Then you can find the length of the corresponding side:

\dfrac{side_{small}}{side_{large}}=k\Rightarrow =\dfrac{side_{small}}{9}=\dfrac{1}{2},\ side_{small}=\dfrac{9}{2}=4.5\ m.

4 0
3 years ago
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