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4 years ago

What is one way engineers have used a material like oobleck to help people?

Chemistry

1 answer:

garri49 [273]4 years ago

6 0

Answer:

Oobleck has been used to manufacture shoes, filling of portholes, making bullet proof vest.

Explanation:

Oobleck is a non Newtonian fluid which is made from mixture of cornstarch and water. It has both liquid and solid properties. Its act like a liquid when is poured and as a solid when a force act on it. It is a substance that is use in manufacturing shoes. The inside layer of shoes is made of it. It's viscosity increases when there is shear stress. It is use for filling portholes

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A sample of neon gas at 102 °C and a volume of 4 liters is cooled to -98 °C. What is the new volume

STALIN [3.7K]

Answer: V= 1.87 L

Explanation: Use Charles Law to solve for the new volume.

V1/T1 = V2/T2 where temperature is in Kelvin. So convert temperature to Kelvin.

4 L ( 175 K ) / 375 K

= 1.87 L

Cancel out both units of K.

8 0

3 years ago

The osmotic pressure of an aqueoussolution of urea at 300 K is

den301095 [7]

<u>Answer:</u> The freezing point of solution is -0.09°C

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=imRT$

where,

$\pi$ = osmotic pressure of the solution = 120 kPa

i = Van't hoff factor = 1 (for non-electrolytes)

m = concentration of solute in terms of molality = ?

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

T = temperature of the solution = 300 K

Putting values in above equation, we get:

$120kPa=1\times m\times 8.31\text{ L kPa }mol^{-1}K^{-1}\times 300K\\\\m=0.05m$

To calculate the depression in freezing point, we use the equation:

$\Delta T=i\times K_f\times m$

where,

i = Vant hoff factor = 1 (for non-electrolytes)

$K_f$ = molal freezing point depression constant = 1.86°C/m

m = molality of solution = 0.05 m

Putting values in above equation, we get:

$\Delta T=1\times 1.86^oC/m\times 0.05m\\\\\Delta T=0.09^oC$

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

The equation used to calculate freezing point of solution is:

$\Delta T=\text{freezing point of water}-\text{freezing point of solution}$

where,

$\Delta T$ = Depression in freezing point = 0.09 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

$0.09^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-0.09^oC$

Hence, the freezing point of solution is -0.09°C

4 0

3 years ago

If the density of nitrogen gas at a certain pressure and temperature is 1.20 g/L, how many moles of nitrogen gas are in 15.0 L.

Irina18 [472]

<h3>Answer:</h3>

0.643 moles

<h3>Explanation:</h3>

We are given;

Density of nitrogen gas as 1.20 g/L

Volume nitrogen as 15.0 L

We are required to calculate the number moles of nitrogen gas;

<h3>Step 1: Determine the mass of nitrogen gas</h3>

We know the density is given by dividing mass by volume.

Density = Mass ÷ volume

Therefore, to get the mass;

Mass = Density × volume
Mass = 1.20 g/L × 15.0 L

= 18 g

<h3>Step 2: Determine the mass of nitrogen gas </h3>

We know that to get the number of moles, we divide mass by molar mass;

That is, moles = Mass ÷ Molar mass

But, molar mass of nitrogen gas is 28 g/mol

Therefore;

Moles of nitrogen gas = 18 g ÷ 28 g/mol

= 0.643 moles

Therefore, the number of moles of nitrogen gas 0.643 moles

5 0

4 years ago

The table below compares the radioactive decay rates of two materials. Material Original mass of material (in grams) Mass of mat

Hoochie [10]

Answer:

The half-life of Material 1 and Material 2 are equal.

Explanation:

Material 1 disintegrates to half its mass three times in 21.6 s, to go from 100g

to 12.5g. That is,

100g - 50g - 25g - 12.5g

Material 2 disintegrates to half its mass three times in 21.6 s, to go from 200g to 25g. That is,

200g - 50g - 25g - 12.5g.

This means that regardless of their initial masses involved, material 1 and material 2 have equal half-life.

Their half-life is 21.6 ÷ 3 = 7.2 sec

5 0

4 years ago

Explain how CO2 is absorbed into the ocean of H2O

Dmitrij [34]

The ocean absorbs CO2 from the atmosphere wherever air meets water. Wind causes waves, giving more opportunity for the water to absorb the carbon dioxide.

7 0

3 years ago