The excerpt from an essay about higher education that most clearly shows an example of logos is:
- Option d: Many college students look to land an exciting internship, believing that it will open doors in their field of study. However, internships can often distract from schoolwork.
<h3>What is Logos?</h3>
The Logos Definition is one that is often argued by a lot of people as people tends to appeal to others emotions and some other times, people do appeal to one's' ethics or morals.
The term logos is a term that connote the use of logic. It also includes the use of deductive reasoning to get to a conclusion.
The excerpt from an essay about higher education that most clearly shows an example of logos is:
- Option d: Many college students look to land an exciting internship, believing that it will open doors in their field of study. However, internships can often distract from schoolwork.
Option d is correct because it shows the cause and its effect.
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Answer:
d = 0.9 g/L
Explanation:
Given data:
Number of moles = 1 mol
Volume = 24.2 L
Temperature = 298 K
Pressure = 101.3 Kpa (101.3/101 = 1 atm)
Density of sample = ?
Solution:
PV = nRT (1)
n = number of moles
number of moles = mass/molar mass
n = m/M
Now we will put the n= m/M in equation 1.
PV = m/M RT (2)
d = m/v
PM = m/v RT ( by rearranging the equation 2)
PM = dRT
d = PM/RT
The molar mass of neon is = 20.1798 g/mol
d = 1 atm × 20.1798 g/mol / 0.0821 atm. L/mol.K × 273K
d = 20.1798 g/22.413 L
d = 0.9 g/L
The molar extinction coefficient is 15,200 .
The formula to be used to calculate molar extinction coefficient is -
A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.
The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.
Rewriting the formula as per molar extinction coefficient -
ξ =
ξ =
Performing multiplication in denominator to find the value of molar extinction coefficient
ξ =
Performing division to find the value of molar extinction coefficient
ξ = 15,200
Hence, the molar extinction coefficient is 15,200 .
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Answer: sorry I’m not sure
Odjri: