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Fofino [41]
3 years ago
13

For the reaction 2NH3(g) + O2(g) -> 2NO(g) + 3H2O(g). The reaction is run using 824 g NH3 and excess oxygen. How many moles o

f NO are formed? How many moles of H2O are formed?
Chemistry
1 answer:
Alex73 [517]3 years ago
4 0

Answer:

Explanation:

Step One

Find the molar Mass of NH3

N =   14

3H =  3

Mass = 17

Step Two

Find the number of moles of NH3

mols = given mass / Molar Mass

given mass = 824 grams

molar mass = 17

mols = 824/17

mols =  48.47

Step Three

Find the moles of NO

Here you have to look at the balanced equation

Every 2 mols of HN3 produces 2 mols of NO

So the number of mols of NH3 = 48.47

The number of mols of  NO      = 48.47

Step Four

Find the mols of H2O

2 mols of NH3 produces 3 moles of H20

48.47 mols H20 produces x moles of H20

3/x = 2/48.47     Cross Multiply

2x = 3*48.47

2x = 145.41         Divide by 2

x = 145.41/2

x = 72.71            mols of water.

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4 years ago
2C6H5COOH + 15O2 → 14CO2 + 6H2O which of the following options gives the correct product:product ratio?
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You did not include the options but I can tell you the product ratio.

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The given equation is: 2 C6H5COOH + 15O2 --> 14 CO2 + 6H2O

The mole ratios are: 2 C6H5COOH: 15 O2: 14 CO2 : 6 H2O

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That can be expressed as:

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----------------- =  -----------------
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It is also the same that:

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