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zubka84 [21]
3 years ago
6

Find the slope containing the points (3,7) and (-4,10)

Mathematics
2 answers:
Monica [59]3 years ago
6 0
  • Slope Formula: \frac{y_2-y_1}{x_2-x_1}

For this, put the two points into the slope formula to solve:

\frac{7-10}{3-(-4)}=-\frac{3}{7}

<u>The slope is -3/7.</u>

melisa1 [442]3 years ago
3 0

The formula of find the slope is -0.4285

use y2 - y1 over x2-x1

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horsena [70]

The equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1

<h3>Equation of a line</h3>

A line is the shortest distance between two points. The equation of a line in point-slope form and perpendicular to a line is given as;

y - y1 = -1/m(x-x1)

where

m is the slope

(x1, y1) is the intercept

Given the following

Point = (4, -1)

Line: 2x-y - 7 = 0


Determine the slope

-y = -2x + 7

y= 2x - 7

Slope = 2

Substitute

y+1 = -1/2(x -4)

Write in slope-intercept form

2(y + 1) = -(x - 4)

2y+2 = -x + 4

2y = -x + 2

y = -1/2 + 1

Hence the equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1

Learn more on equation of a line here: brainly.com/question/13763238

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4 0
2 years ago
Find (x+3) (x^2 - 2x -8). Write answer in standard form
Pavlova-9 [17]

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Step-by-step explanation:

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insens350 [35]
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You pick a card at random, put it back, and then pick another card at random.
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Step-by-step explanation:

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JulijaS [17]

Note: The equations written in this questions are not appropriately expressed, however, i will work with hypothetical equations that will enable you to solve any problems of this kind.

Answer:

For the system of equations to be unique, s can take all values except 2 and -2

Step-by-step explanation:

2sx_{1} + 4x_{2} = -3\\2x_{1} + sx_{2} = 4

\left[\begin{array}{ccc}2s&4\\2&s\end{array}\right] \left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right] = \left[\begin{array}{ccc}-3 \\6 \end{array}\right]

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