38, 20, 12, 2, 1 and 4 only.
Answer:
10/16 (written as a fraction)
Step-by-step explanation:
Starting point
-(-2x+1)=9-14x
Solve the minus sign
2x-1=9-14x
Swap the Xs and the numbers, changing sign
2x+14x=9+1
Do calculations
16x=10
Result
x=10/16
The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
Read more about Algebra Word Problems at; brainly.com/question/21405634
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Answer:
800. Here's why:
Step-by-step explanation:
This indicats that 440 students make up 55% of the 6th grade population. We can write this as
55/440.
We also know that 'x' total students make up 100% of the 6th-grade population, so we can write this as
100/x.
55/440 must be equal to 100/x. When cross multiplied, it becomes 50x=44000. If we divided each side by 50, we'll find that x=880. Therefore, there are 800 6th graders
Solving this inequality:
-6>t-(-13)
solve as an equation;
6>t+13
6-13>t
-7>t
-7 is greater than t, which means that can be any number smaller that t, fir instance -8, -22 etc.
