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3 years ago

Solve the system of equations by the substitution method.

1 answer:

6 0

We can substitute the second into the first, this gives:

x -5x = -24 =>
-4x = -24
x = 6

fill in this x value in the second equation:

y = -5*6 = -30

So the solution is x=6, y=-30

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What is the probability of an event that is certain?

horrorfan [7]

Answer:

Step-by-step explanation:

An event that is certain to happen has a probability of 1.

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3 years ago

20 equals more than a number y

riadik2000 [5.3K]

Answer:

$20 > y$

Step-by-step explanation:

20 is greater than y.

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3 years ago

suppose that the lifetime of a transistor is a gamma random variable x with mean of 24 weeks and standard deviation of 12 weeks.

emmainna [20.7K]

The probability that the transistor will last between 12 and 24 weeks is 0.424

X= lifetime of the transistor in weeks E(X)= 24 weeks

O,= 12 weeks

The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.

X~gamma( $\alpha ,\beta$ )

E(X)= $\alpha \beta$ $\beta$ = $12^{2}/24$ =6 weeks

V(x)= $\alpha \beta ^{2}$ $\alpha$ =24/6= 4

Now we can find the solutions:

The excel formula used to create Figure one is as follows:

=gammadist(X, $\alpha$ , $\beta$ , False)

P( $12\leq X\leq 24$ )

P( $12/6\leq G\leq 24/6$ )

P( $2\leq G\leq 4$ )

P= 0.424

Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424

To learn more about probability click here:

brainly.com/question/11234923

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4 0

1 year ago

Read 2 more answers

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mina [271]

"A dozen eggs and a dozen jellybeans" is the one comparison among the following choices given in the question that a teacher would most likely use for describing a mole. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has helped you.

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3 years ago

Read 2 more answers

The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 73 minutes and a standard devi

Vesnalui [34]

Answer:

(a) $X\sim N(\mu = 73, \sigma = 16)$

(b) 0.7910

(d) 0.6464

Step-by-step explanation:

Let X = amount of time that people spend at Grover Hot Springs.

The random variable X is normally distributed with a mean of 73 minutes and a standard deviation of 16 minutes.

(a)

The distribution of the random variable X is:

$X\sim N(\mu = 73, \sigma = 16)$

(b)

Compute the probability that a randomly selected person at the hot springs stays longer than 60 minutes as follows:

$P(X>60)=P(\frac{X-\mu}{\sigma}>\frac{60-73}{16})\\=P(Z>-0.8125)\\=P(Z$

*Use a z-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays longer than an hour is 0.7910.

(c)

Compute the probability that a randomly selected person at the hot springs stays less than 45 minutes as follows:

$P(X$

*Use a z-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays less than 45 minutes is 0.0401.

(d)

Compute the probability that a randomly person spends between 60 and 90 minutes at the hot springs as follows:

$P(60$

*Use a z-table for the probability.

Thus, the probability that a randomly person spends between 60 and 90 minutes at the hot springs is 0.6464

6 0

3 years ago