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yarga [219]
3 years ago
14

Solve the system of equations by the substitution method.

Mathematics
1 answer:
xeze [42]3 years ago
6 0
We can substitute the second into the first, this gives:

x -5x = -24 =>
-4x = -24
x = 6

fill in this x value in the second equation:

y = -5*6 = -30

So the solution is x=6, y=-30
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The tables represent the functions f(x) and g(x).
dolphi86 [110]

A function assigns the values. The correct option is C, x=-6.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

A.) When the value of x is -12,

f(-12) = 2/3(-12) + 7 = -1

g(-12) = 2(-12) + 15 = -9

B.) When the value of x is -9,

f(-9) = 2/3(-9) + 7 = 1

g(-9) = 2(-9) + 15 = -3

C.) When the value of x is -6,

f(-6) = 2/3(-6) + 7 = 3

g(-6) = 2(-6) + 15 = 3

D.) When the value of x is -3,

f(-9) = 2/3(-3) + 7 = 5

g(-9) = 2(-2) + 15 = 11

Hence, the correct option is C, x=-6.

Learn more about Function:

brainly.com/question/5245372

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4 0
2 years ago
What is this question?​
Vlad [161]

Answer:

3 buses and 5 cars

Step-by-step explanation:

3 0
2 years ago
A soft-drink machine at a steakhouse is regulated so that the amount of drink dispensed is normally distributed with a mean of 2
AnnZ [28]

Answer:

z=\frac{203-200}{\frac{15}{\sqrt{9}}}=0.6    

p_v =P(z>0.6)=0.274  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can't conclude that the true mean is not significantly higher than 200 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=203 represent the mean height for the sample  

\sigma=15 represent the population standard deviation

n=9 sample size  

\mu_o =200 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 200, the system of hypothesis would be:  

Null hypothesis:\mu \leq 200  

Alternative hypothesis:\mu > 20  

If we analyze the size for the sample is < 30 but we  know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{203-200}{\frac{15}{\sqrt{9}}}=0.6    

P-value

Since is a one sided test the p value would be:  

p_v =P(z>0.6)=0.274  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can't conclude that the true mean is not significantly higher than 200 at 5% of signficance.  

8 0
3 years ago
Find the common factor of all of the terms of the polynomial below.
Kaylis [27]

Answer:

Step-by-step explanation:

d 4x

5 0
3 years ago
Read 2 more answers
The area is Arizona covered by desert is about 5880 square miles. If 42% of the total area is desert how many square miles is ar
Anna [14]
Total Area<span>0.42*TotalArea = 5880 <span>Hence TotalArea = 5880/0.42 = 14000 sq ft </span></span>
6 0
3 years ago
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