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Hitman42 [59]
3 years ago
5

Question 1 or 10

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:

C. y-2 = 4(x+1)

Step-by-step explanation:

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mariarad [96]

Answer:

A. Domain : (-∞, ∞)

B. Function is increasing in the interval (-2, 0) and (2, ∞)

   Decreasing in the interval of (-∞, -2) and (0, 2).

Step-by-step explanation:

A. Given function is, y = |2x - 1|

This function is the transformed form of the parent function, y = |x|

Domain of the parent function is { x | x is a set of real numbers}

Therefore, domain of the transformed function will be the same as the domain of the parent function.

Domain of the function = {x | x is a real number}

B. Given function is f(x) = (x^2-4) ^{\frac{2}{3} }

Domain of the function : (-∞, ∞)

Critical points of the function are,

⇒ x = 0, ±2

Now we find the three intervals where we have to check the function to be increasing or decreasing.

(-∞ -2), (-2, 0), (0, 2), (2, ∞)

Derivative of the function f(x),

f'(x) = \frac{4x}{3(x^2-4)^{\frac{1}{3} } }

Here, f'(x) < 0 for (-∞, -2)

f'(x) > 0 for (-2, 0)

f'(x) < 0 for (0, 2)

f'(x) > 0 for (2, ∞)

Therefore, given function is increasing in the interval (-2, 0) and (2, ∞)

And it's decreasing in the interval of (-∞, -2), and (0, 2).

6 0
3 years ago
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