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gulaghasi [49]
3 years ago
7

1. Suppose you pay back $680 on a $650 loan you had for 75 days. What was your simple annual interest rate?

Mathematics
1 answer:
harina [27]3 years ago
3 0

well, let's assume a year has 365 days, so 75 days is simply 75/365 of a year.  We also know that your loan was $650 and you paid back $680 or namely 30 bucks extra, so the interest on those $650 is really 30 bucks.

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &\$30\\ P=\textit{original amount deposited}\dotfill & \$650\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\to \frac{75}{365}\dotfill &\frac{15}{73} \end{cases} \\\\\\ 30 = (650)(\frac{r}{100})(\frac{15}{73})\implies 30=\cfrac{9750r}{7300}\implies 30=\cfrac{195r}{146}\implies 4380=195r \\\\\\ \cfrac{4380}{195}=r\implies \stackrel{\%}{22.46}\approx r

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After three weeks, he has gone from 20 free throws to 26. By what percent has he increased his score?
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Answer:

By 30%

Step-by-step explanation

He has improved by 6 free throws. He used to score 20 points from free throws(Im assuming this is basketball) He scores 6 more in three weeks.

6/20 = 30/100=30 percent.

Check:

30% of 20  = 6

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4 0
3 years ago
The mean of the temperatures in the chart is 24° with standard deviation of 4°. How many years had temperatures within one stand
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Answer:

Step-by-step explanation:

Given: The mean of the temperatures in the chart is 24° and standard deviation is 4°.

To find: How many years had temperatures within one standard deviation of the mean

Solution: Mean temperature μ = 24 , standard deviation σ =4

The lower and upper bound for temperature within one standard deviation of the mean is given as:

Lower bound = μ - σ = 24 - 4=20

Thus, the Lower bound is = 20

Upper bound = μ + σ = 24+ 4=28

Thus, the Upper bound is = 28

Now, The temperature value between (Lower bound, Upper bound) that is (20, 28) is said to be within one standard deviation of the mean.

Hence 27° is the temperature value that is within one standard deviation of mean.

5 0
3 years ago
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Answer:

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