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Phantasy [73]
3 years ago
9

Use the Distributive Property to find the price of 5 CDs that cost $15.99 each.

Mathematics
2 answers:
Stells [14]3 years ago
4 0

Answer:

75.95 is the sum

blsea [12.9K]3 years ago
3 0
15,99*5=79.95

The answer is 79,95 $
You might be interested in
1+1+2+2+3+3+4+4+5+5+6+6+7+7+8+8+9+9+0+0
Rama09 [41]

90

6+6=12

12+8=20

20+10=30

30+12=42

42+14=56

56+16+18=90

4 0
3 years ago
Read 2 more answers
Please answer I am struggling
blsea [12.9K]

(For question 1 you have to do it yourself, get a ruler and measure the actual length of the drawing, then multiply it by 8 to get the actual dimensions in the exercise. )

Example, if you measure 4 inches, the actual dimension will be 4 x 8 = 32 ft

2. (Scale drawing 1:5 is that every 1 (length units) will be equal to 5(length units) in the actual dimensions)

Model : 3ft ; 7m
Actual : 15ft ; 35m (corresponding)

Actual : 20yd ; 12.5 cm
Model : 4yd ; 2.5 cm

6. 1.5 ft = 1.5 x 12 = 18 inches.
The model is 3 inches, and the actual rose is 18 inches -> The scale of the drawing is 6. (enlargement)

Same goes to the scale factor, but this time is the quotient of the corresponding side -> 3 : 18 = 1:6.

(If I got any parts wrong just tell me, I actually kinda forgot these kind of stuff)


8 0
3 years ago
Select all that apply.
Kryger [21]

Answer:

Your answer would be

1 \times 3 = 3

And

3 \times 5 = 15

Step-by-step explanation:

Hope this helps. If I am wrong, REPORT ME PLEASE.

6 0
2 years ago
John joined a gym for 6 months. He pays 20$ per month plus a membership fee. If his bill is 150$, what was the membership fee?
Jlenok [28]

Answer:

Step-by-step explanation:

If he's been at the gym for 6 months, and he is charged $20 each month, then he has paid $120 dollars, not counting his membership fee. His total bill is $150.

150-120= $30

His membership fee was $30.

Hope this helps!

Mark Brainliest plz!

3 0
3 years ago
Read 2 more answers
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
3 years ago
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