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tester [92]
2 years ago
9

Please answer I am struggling

Mathematics
1 answer:
blsea [12.9K]2 years ago
8 0

(For question 1 you have to do it yourself, get a ruler and measure the actual length of the drawing, then multiply it by 8 to get the actual dimensions in the exercise. )

Example, if you measure 4 inches, the actual dimension will be 4 x 8 = 32 ft

2. (Scale drawing 1:5 is that every 1 (length units) will be equal to 5(length units) in the actual dimensions)

Model : 3ft ; 7m
Actual : 15ft ; 35m (corresponding)

Actual : 20yd ; 12.5 cm
Model : 4yd ; 2.5 cm

6. 1.5 ft = 1.5 x 12 = 18 inches.
The model is 3 inches, and the actual rose is 18 inches -> The scale of the drawing is 6. (enlargement)

Same goes to the scale factor, but this time is the quotient of the corresponding side -> 3 : 18 = 1:6.

(If I got any parts wrong just tell me, I actually kinda forgot these kind of stuff)


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Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

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Step-by-step explanation:

Part A) Graph the function

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t -----> the time in seconds

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so

x=0 ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point (0,98)

The y-intercept is the point (0,98)

The t-intercepts are (-2.475,0), (2.475,0)

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

h(t)=-16(0)^{2}+98

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h(t)=-16(1)^{2}+98

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98\ ft-82\ ft=16\ ft

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

h(t)=-16(1)^{2}+98

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For t=2

h(t)=-16(2)^{2}+98

h(2)=34\ ft

Find the difference

82\ ft-34\ ft=48\ ft

so

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from  t=0 to t=1

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i am sorry in never answeres ur question but pls can u help me i am struggling

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