Idk what the answers is sorry
Answer:
The area of the shape is
.
Step-by-step explanation:
The shape in the graph is a composite figure is made up of several simple geometric figures such as triangles, and rectangles.
Area is the space inside of a two-dimensional shape. We can also think of area as the amount of space a shape covers.
To calculate the area of a composite shape you must divide the shape into rectangles, triangles or other shapes you can find the area of and then add the areas back together.
First separate the composite shape into three simpler shapes, in this case two rectangles and a triangle. Then find the area of each figure.
To find the area of a rectangle, we multiply the length of the rectangle by the width of the rectangle.
The area of the first rectangle is ![A=34\cdot 16=544\:cm^2](https://tex.z-dn.net/?f=A%3D34%5Ccdot%2016%3D544%5C%3Acm%5E2)
The area of the second rectangle is ![A=11\cdot19=209\: cm^2](https://tex.z-dn.net/?f=A%3D11%5Ccdot19%3D209%5C%3A%20cm%5E2)
The area of a triangle is given by the formula
where <em>b</em> is the base and <em>h</em> is the height of the triangle.
The area of the triangle is ![A=\frac{1}{2} \cdot 14\cdot19=133\:cm^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%20%5Ccdot%2014%5Ccdot19%3D133%5C%3Acm%5E2)
Finally, add the areas of the simpler figures together to find the total area of the composite figure.
![A_{composite\:shape}=544+209+133=886 \:cm^2](https://tex.z-dn.net/?f=A_%7Bcomposite%5C%3Ashape%7D%3D544%2B209%2B133%3D886%20%5C%3Acm%5E2)
Answer:
C
Step-by-step explanation:
i am smart
DOCK
HIKE
CHOKE
FISH does not work because the S is not horizontally symmetric.
BONE doesn't work because the N is not horizontally symmetric.
Answer:
Yumiko should multiply the other equation by 3.
If she adds the two equations she would be left with the variable 'x'.
Step-by-step explanation:
Given the two equations are as follows:
![$ 2x - 3y = 12 \hspace{5mm} \hdots (1) $](https://tex.z-dn.net/?f=%24%202x%20-%203y%20%3D%2012%20%5Chspace%7B5mm%7D%20%5Chdots%20%281%29%20%24)
![$ 5x + 6y = 18 \hspace{5mm} \hdots (2) $](https://tex.z-dn.net/?f=%24%205x%20%2B%206y%20%3D%2018%20%5Chspace%7B5mm%7D%20%5Chdots%20%282%29%20%24)
It is given that she multiplies the first equation by 6. Therefore, (1) becomes
![$ 12x - 18y = 72 \hspace{15mm} \hdots (a) $](https://tex.z-dn.net/?f=%24%2012x%20-%2018y%20%3D%2072%20%5Chspace%7B15mm%7D%20%5Chdots%20%28a%29%20%24)
Now, note that the sign of the variable 'y' is negative. So, if we make the co-effecient of 'y' equal in both the cases, add them it would result in the elimination of the variable 'y'.
The co-effecient of y in Equation (2) is 6. To make it 18 like it is in Equation (1), we multiply throughout by 3.
Therefore, Equation (2) becomes:
![$ 15x + 18y = 54 \hspace{5mm} \hdots (b) $](https://tex.z-dn.net/?f=%24%2015x%20%2B%2018y%20%3D%2054%20%5Chspace%7B5mm%7D%20%5Chdots%20%28b%29%20%24)
Now, we add Equation (a) and Equation (b).
![$ \implies 12x - 18y + 15x + 18y = 72 + 54 $](https://tex.z-dn.net/?f=%24%20%5Cimplies%2012x%20-%2018y%20%2B%2015x%20%2B%2018y%20%3D%2072%20%2B%2054%20%24)
![$ \implies 27x = 126 $](https://tex.z-dn.net/?f=%24%20%5Cimplies%2027x%20%3D%20126%20%24)
Factor: 3
Equation: 27x = 126