Question

A survey of athletes at a high school is conducted, and the following facts are discovered: 57% of the athletes are football players, 17% are basketball players, and 8% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that the athlete is either a football player or a basketball player?

Answer 1

Answer:

The probability that the athlete is either a football player or a basketball player = $\frac{66}{100}$ = 0.66

Step-by-step explanation:

Football players = 57 %

Basketball players = 17 %

Both game players = 8 %

Players who plays either one game = ( Football players ) + ( Basketball players)  - ( Both game players )

⇒ 57 + 17 - 8 = 66 %

Now, the probability that the athlete is either a football player or a basketball player = $\frac{66}{100}$ = 0.66