The square prism has a base length of 2 ft. Which describes the cross section of the prism that is perpendicular to

Find an equation of the circle that satisfies the given conditions. (Give your answer in terms of x and y.) Center at the origin

Elanso [62]

Answer:

The equation of circle is $x^2+y^2=65$ .

Step-by-step explanation:

It is given that the circle passes through the point (8,1) and center at the origin.

The distance between any point and the circle and center is called radius. it means radius of the given circle is the distance between (0,0) and (8,1).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula the radius of circle is

$r=\sqrt{\left(8-0\right)^2+\left(1-0\right)^2}=\sqrt{65}$

The standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$ .... (1)

where, (h,k) is center and r is radius.

The center of the circle is (0,0). So h=0 and k=0.

Substitute h=0, k=0 and $r=\sqrt{65}$ in equation (1).

$(x-0)^2+(y-0)^2=(\sqrt{65})^2$

$x^2+y^2=65$

Therefore the equation of circle is $x^2+y^2=65$ .

5 0

3 years ago

A rectangle has a perimeter of 26 units. The length of the rectangle is 2X+3 and the width is 3X. What is the width of the recta

densk [106]

Answer:

X = 2

Step-by-step explanation:

Divided 26 (total perimeter) by 4 = maximum side length possible = 26÷4 =.6.5

I used the trial and error technique

Guessed it was 2 working out to see if i was right or wrong:

Length: 2(2) + 3 = 4+3 = 7

Width: 3(2) = 6

7+7+6+6 = 26

Therefore X = 2

3 0

3 years ago

A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken

mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

$X=1$ number of citrus trees that are infected with the citrus red mite.

$n=5$ random sample taken

$\hat p=\frac{1}{5}=0.2$ estimated proportion of citrus trees that are infected with the citrus red mite.

$p$ true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values would be given by:

$t_{\alpha/2}=-1.96, t_{1-\alpha/2}=1.96$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.01$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.2(1-0.2)}{(\frac{0.01}{1.96})^2}=6146.56$

And rounded up we have that n=6147

5 0

3 years ago

Help me with this one

vaieri [72.5K]

Plant (A) have a higher median at 6 and the IQR is low at 3, however, Plant (B) has a lower median of 5 but High IQR of 4 so the Plant (B) is growth is high.
hopes loves.

3 0

3 years ago

A singles tennis court is a rectangle 27 feet wide and 78 feet long. Suppose a player at corner A hits the ball to her opponent

Sav [38]

Basically, you just have to find the length of the rectangle that is 27 x 78 feet.
The equation for the diagonal:
d = sqrt(l^2+w^2)
l = 27
w = 78
plug them in and solve
d = sqrt ( (27^2) + (78^2) )
d = sqrt ( 729 + 6084 )
d = sqrt ( 6813 )
d <span>≈ 82.5

The ball traveled approximately 82.5 feet from one corner of the rectangular 27 x 78 foot field, diagonally to the other side.

Hope this helps</span>

6 0

3 years ago