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Vesnalui [34]
3 years ago
15

47 + 34 = 3k + 3k + 3k solve for k

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
6 0

Answer:

Step-by-step explanation:

47+34=9k

81=9k

k=81/9=9

k=9

Dovator [93]3 years ago
3 0

Step-by-step explanation:

81 = 9k

/9 /9

9 = k

I found this to be the right awnser, hope this helps.

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Can somebody please help me its for a test grade :((
skelet666 [1.2K]

Answer:

B

Step-by-step explanation:

To solve this you have to figure out how many pints are needed to get a gallon so you have pints which there should be 4 pints but you need more than 4 pints to make a gallon so multiply that by 2 then divide how much a gallon is to get the number of pints they drank in a week

8 0
3 years ago
Read 2 more answers
The chance of rain on a randomly selected day in Western Oregon between June 21st and September 21st is 30% each day. What is th
polet [3.4K]

Answer:

0.47 is the probability it rains at least 2 out of any randomly selected 5 days during the given time of year

Step-by-step explanation:

We are given the following information:

We treat training as a success.

P(Rain) = 30% = 0.30

Then the chances of rain on each day follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 5

We have to evaluate:

P(x \geq 2) =1- P(x = 0) + P(x = 1) \\=1- \binom{5}{0}(0.3)^0(1-0.3)^5 - \binom{5}{1}(0.3)^1(1-0.3)^4\\=1- 0.16807- 0.36015\\= 0.47178 \approx 0.47

0.47 is the probability it rains at least 2 out of any randomly selected 5 days during the given time of year

6 0
4 years ago
Find the midpoint of CD if C(3.5) and D(7.5).
Artyom0805 [142]

Answer:

5.5

Step-by-step explanation:

Add the two then divide by 2

7.5 +3.5= 11

11÷2= 5.5

6 0
3 years ago
Members of the theater club sold tickets for the spring
DerKrebs [107]

Answer:

C. 125 + 120x = 180 + 110x

t = $5.5

Step-by-step explanation:

A.125t + 120 = 180t + 110

B. 120t + 110t = 125 + 180

C. 125 + 120t = 180 + 110t

D. 125 - 120t = 180 - 110t

Friday

$125 + 120t

Saturday

110t + 180

equate Friday and Saturday

125 + 120t = 110t + 180

Collect like terms

125 - 180 = 110t - 120t

-55 = -10t

Divide both sides by -10

t = -55 / -10

= 5.5

t = $5.5

6 0
3 years ago
Lim x-->+ infinity (2^x)/x^10
nadezda [96]
\displaystyle\lim_{x\to\infty}\frac{2^x}{x^{10}}=\lim_{x\to\infty}\frac{e^{x\ln2}}{x^{10}}=\dfrac\infty\infty

A few applications of L'Hopital's rule gives a decent idea of how this limit will ultimately behave.

=\displaystyle\lim_{x\to\infty}\frac{\ln2\,e^{x\ln2}}{10x^9}
=\displaystyle\lim_{x\to\infty}\frac{(\ln2)^2\,e^{x\ln2}}{90x^8}

and so on. Notice that the numerator will consistently behave exponentially, while the denominator will eventually be rendered into a constant. This means the function diverges to \infty as x\to\infty.
6 0
3 years ago
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