Putting numbers from scientific notation to standard notation

Asp helppp will mark brainliest

masya89 [10]

Answer:

football cricket

male 0.56 0.16 0.72

female 0.09 0.19 0.28

0.65 0.35 1

6 0

3 years ago

Use the parabola tool to graph the quadratic function f(x)=x2−12x+27. Graph the parabola by first plotting its vertex and then p

alina1380 [7]

Answer:

vertex is (6 , -9)

points are (9,0) and (3,0)

Step-by-step explanation:

Given quadratic function $f(x)=x^2-12x+27$

We have to plot the given quadratic function.

Consider the Given quadratic function $f(x)=x^2-12x+27$

The general form of quadratic function is given $f(x)=a(x-h)^2+k$

Where, (h, k) is vertex , given $h =\frac{-b}{2a}$ and $k = f(h)$

Thus, for given quadratic function $f(x)=x^2-12x+27$

a = 1 , b= -12 , c = 27

Thus,

$h =\frac{-b}{2a}=\frac{12}{2}=6$

$k = f(h)$ that is f(12) = (6)^2 - 12× 6 +27 = 36 - 72 + 27 = - 9

Thus, given quadratic function $f(x)=x^2-12x+27$ in standard form is $f(x)=(x-6)^2-9$

Thus, vertex is (6 , -9)

For second point put $f(x)=0$ , we get,

$f(x)=(x-6)^2-9=0$

$\Rightarrow (x-6)^2-9=0$

$\Rightarrow (x-6)^2=9$

$\Rightarrow (x-6)=\pm 3$

$\Rightarrow x= 6\pm 3$

Thus, $\Rightarrow x=6+3=9$ and $\Rightarrow x=6-3=3$

thus, points are (9,0) and (3,0)

Graph is attached below.

5 0

4 years ago

What is the solution to the system of equations Use the substitution method to solve the system of equations. Show your work.

marishachu [46]

Answer:

Step-by-step explanation:

Let's work to solve this system of equations:

y = 2x ~~~~~~~~\gray{\text{Equation 1}}y=2x Equation 1

x + y = 24 ~~~~~~~~\gray{\text{Equation 2}}x+y=24 Equation 2

The tricky thing is that there are two variables, xx and yy. If only we could get rid of one of the variables...

Here's an idea! Equation 11 tells us that \goldD{2x}2x and \goldD yy are equal. So let's plug in \goldD{2x}2x for \goldD yy in Equation 22 to get rid of the yy variable in that equation:

\begin{aligned} x + \goldD y &= 24 &\gray{\text{Equation 2}} \\\\ x + \goldD{2x} &= 24 &\gray{\text{Substitute 2x for y}}\end{aligned}

x+y

x+2x

=24

Equation 2

Substitute 2x for y

Brilliant! Now we have an equation with just the xx variable that we know how to solve:

x+2x3x 3x3x=24=24=243=8Divide each side by 3

Nice! So we know that xx equals 88. But remember that we are looking for an ordered pair. We need a yy value as well. Let's use the first equation to find yy when xx equals 88:

\begin{aligned} y &= 2\blueD x &\gray{\text{Equation 1}} \\\\ y &= 2(\blueD8) &\gray{\text{Substitute 8 for x}}\\\\ \greenD y &\greenD= \greenD{16}\end{aligned}

y

=2x

=2(8)

=16

Equation 1

Substitute 8 for x

Sweet! So the solution to the system of equations is (\blueD8, \greenD{16})(8,16). It's always a good idea to check the solution back in the original equations just to be sure.

Let's check the first equation:

\begin{aligned} y &= 2x \\\\ \greenD{16} &\stackrel?= 2(\blueD{8}) &\gray{\text{Plug in x = 8 and y = 16}}\\\\ 16 &= 16 &\gray{\text{Yes!}}\end{aligned}

y

16

=2x

=

?

2(8)

=16

Plug in x = 8 and y = 16

Yes!

Let's check the second equation:

\begin{aligned} x +y &= 24 \\\\ \blueD{8} + \greenD{16} &\stackrel?= 24 &\gray{\text{Plug in x = 8 and y = 16}}\\\\ 24 &= 24 &\gray{\text{Yes!}}\end{aligned}

x+y

8+16

24

=24

=

?

24

=24

Plug in x = 8 and y = 16

Yes!

Great! (\blueD8, \greenD{16})(8,16) is indeed a solution. We must not have made any mistakes.

Your turn to solve a system of equations using substitution.

Use substitution to solve the following system of equations.

4x + y = 284x+y=28

y = 3xy=3x

7 0

4 years ago

Please actually show ur work on how u got the answer thank u

serg [7]

Answer:

C

Step-by-step explanation:

I substituted the x value with the different options. I kept doing that until the equation made sense.

4 0

3 years ago

Read 2 more answers

URGENT! very easy help can anyone help

choli [55]

Answer:

i would cry if i had to do this tbh like math is so hard

Step-by-step explanation:

8 0

3 years ago