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3 years ago

Please actually show ur work on how u got the answer thank u

Mathematics

2 answers:

k0ka [10]3 years ago

5 0

Answer:

b) x = 7

Step-by-step explanation:

16+5x = x+12

Subtract 16 from both sides

5x = x+28

subtract x from both sides

4x = 28

divide 4 from both sides

x = 7

Hope this helps :)

serg [7]3 years ago

4 0

Answer:

Step-by-step explanation:

I substituted the x value with the different options. I kept doing that until the equation made sense.

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3 years ago

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Alex17521 [72]

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3 years ago

Abigail is raising money for a school trip by selling bags of chips and packs of cookies. The price of each bag of chips is $1.5

Mkey [24]

The number of bags of chips sold is 8 and the number of packs of cookies sold is 12

<em><u>Solution:</u></em>

Let "a" be the number of bags of chips sold

Let "b" be the number of packs of cookies sold

Given that,

Cost of one bag of chips = $ 1.50

Cost of one pack of cookies = $ 1.25

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<em><u>So we can frame a equation as:</u></em>

Number of bags of chips sold + number of packs of cookies sold = 20

a + b = 20 ---- eqn 1

Also given that Abigail made $27 from selling

number of bags of chips sold x Cost of one bag of chips + number of packs of cookies sold x Cost of one pack of cookies = $ 27

$a \times 1.50 + b \times 1.25 = 27$

1.5a + 1.25b = 27 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "b"</u></em>

From eqn 1,

a = 20 - b ---- eqn 3

Substitute eqn 3 in eqn 2

1.5(20 - b) + 1.25b = 27

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3 years ago

Please help me simplify this<br>

algol [13]

Answer:

................................

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3 years ago

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Digiron [165]

The number of ways to choose the colors is 36

<h3>How to determine the number of ways?</h3>

The given parameters are:

Colors = 9

Colors to choose = 7

Since order does not matter, then it is combination

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

This gives

$^nC_r = \frac{9!}{7!2!}$

Evaluate

$^nC_r = 36$

Hence, the number of ways is 36