Answer:
Option A is correct
The function has real zeroes at x =-10 and x =-6
Explanation:
Given: The real zeroes or roots are x = -10, and x = -6
To find the quadratic function of degree 2.
where α,β are real roots. ....[1]
Here, α= -10 and β= -6
Sum of the roots:
α+β = -10+(-6) = -10-6 = -16
Product of the roots:
αβ = (-10)(-6)= 60
Substitute these value in equation [1] we have;
Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;
Answer: x = 184°
Step-by-step explanation: As we can see in the figure below, angles 2 and 4 are <u>Vertical</u> <u>Angles</u>, i.e., they are angles opposite each other when two lines cross. Vertical angles are always congruent.
Then,
m∠2 = m∠4
Value of x is
x = 184
The value of x is 184°.
Answer: 50
Step-by-step explanation:
4×50= 200
Answer:
5 < a+k
Step-by-step explanation:
This should be it as you said write it out as an expression.