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kherson [118]
4 years ago
11

The following show a change of scale made by an architect in one of his drawings.Old: 1 in. =16 cm. New:1in. =2cm Which is the c

hange in scale factor from the old scale to the new scale?
Mathematics
2 answers:
Varvara68 [4.7K]4 years ago
8 0
The scale factor changes by 1/8.

The numerator, 1 stays the same; the denominator changes. 16/2 = 8; it is 1/8 the scale of the previous scale.
Komok [63]4 years ago
7 0

Answer:

The scale factor changes by 1/8.

Step-by-step explanation:

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nevsk [136]

Answer:

950

Step-by-step explanation:

2500(0.076)(5)  = 950

6 0
3 years ago
Solve this problem please
djyliett [7]

The formula for depreciation is:

y=x(1-r)^t

Where x = Initial value,

y= Amount after depreciation.

r= Rate of depreciation,

t = time (in years)

According to given problem,

x = 1040, y= 944 and t = 12 months =1 year.

So, first step is to plug in these values in the above formula, So,

944 = 1040(1-r)^1

944 = 1040 (1 -r)

\frac{944}{1040} =1-r Divide each sides by 1040.

0.907692308 =1 - r

0.907692308 - 1 = -r Subtract 1 from each sides.

-0.092307692 = -r

So, r = 0.09 or 9%.

Now plug in 0.09 in the above equation to get the depreciation equation. So,

y = x (1- 0.09)^t

So, y = 0.91x^t

b) To find the value of the bike after 5 months,

plug in t = 5 months= 5/12 = 0.41667 years in the above equation of depreciation.

So, y= 1040 *(0.91)^{0.41667}

y = 1040 * 0.961465659

y = 999.9242852

y = 1000 (Rounded to nearest integer).

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7 0
3 years ago
The rectangular bar is connected to the support bracket with a 10-mm-diameter pin. The bar width is w = 70 mm and the bar thickn
german

Answer:

P_max = 9.032 KN

Step-by-step explanation:

Given:

- Bar width and each side of bracket w = 70 mm

- Bar thickness and each side of bracket t = 20 mm

- Pin diameter d = 10 mm

- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa

- Average allowable shear stress of pin S = 115 MPa

Find:

The maximum force P that the structure can support.

Solution:

- Bearing Stress in bar:

                                       T = P / A

                                       P = T*A

                                       P = (120) * (0.07*0.02)

                                       P = 168 KN

- Shear stress in pin:

                                        S = P / A

                                        P = S*A

                                        P = (115)*pi*(0.01)^2 / 4

                                        P = 9.032 KN

- Bearing Stress in each bracket:

                                       T = P / 2*A

                                       P = T*A*2

                                       P = 2*(120) * (0.07*0.02)

                                       P = 336 KN

- The maximum force P that this structure can support:

                                      P_max = min (168 , 9.032 , 336)

                                      P_max = 9.032 KN

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Answer: 0.0

Step-by-step explanation:

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