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LenaWriter [7]
3 years ago
8

Carlson city and mason city are 15 miles apart. if you leave carlson city and drive at 45 miles per hour, how long does it take

you to reach mason city?
Mathematics
1 answer:
Yanka [14]3 years ago
5 0
Using the formula for distance-speed and time, i, e, s=v*t, we can find the answer. Since s=15 miles, v=45 mph, then t=s/v=15/45 hours=1/3 hours=20 minutes.
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Step-by-step explanation:

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Hey there :)

( 5y + 9 )( 6y - 1 )

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Please help me in this questions....​
Ivahew [28]

Part (i)

I'm going to use the notation T(n) instead of T_n

To find the first term, we plug in n = 1

T(n) = 2 - 3n

T(1) = 2 - 3(1)

T(1) = -1

The first term is -1

Repeat for n = 2 to find the second term

T(n) = 2 - 3n

T(2) = 2 - 3(2)

T(2) = -4

The second term is -4

<h3>Answers: -1, -4</h3>

==============================================

Part (ii)

Plug in T(n) = -61 and solve for n

T(n) = 2 - 3n

-61 = 2 - 3n

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n = -63/(-3)

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Note that plugging in n = 21 leads to T(21) = -61, similar to how we computed the items back in part (i).

<h3>Answer:  21st term</h3>

===============================================

Part (iii)

We're given that T(n) = 2 - 3n

Let's compute T(2n). We do so by replacing every copy of n with 2n like so

T(n) = 2 - 3n

T(2n) = 2 - 3(2n)

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T(n) - T(2n) = 3n

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n = 24/3

n = 8

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<h3>Answer: 8</h3>
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