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nordsb [41]
4 years ago
12

Neela’s clock is broken. The minute hand rotates around the clock correctly, but the hour hand is stuck in the three o’clock pos

ition. Suppose Neela first looks at the clock when the hands are aligned and it shows 3:15. She looks at the clock again and sees that the hour and minute hands of the clock form the arms of an angle measuring −105°. Through which of the following could the minute hand have rotated to reach its current position? −465° −375° −435° −95°
Mathematics
1 answer:
lesantik [10]4 years ago
6 0
-465° This is because one full rotation is 360° and since it's a negative degree (-105°) the answer has to be a negative number that is less than -360°. So what you would do is 360+105, to find a number that if the operation is reverse you get one of the numbers. This gives you positive 465, then you subtract 465 from 360 (360-465) and you get -105.
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Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant.  But maybe you don't know it isn't and it's a "trick" to throw you off.  Hmm...

Anyways, the half angle identity for tangent is

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There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.  

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5.  That makes the missing side, by Pythagorean's Theorem, -3.  Filling in our formula:

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) } which simplifies a bit to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }  and a bit more to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }

Bring up the lower fraction and flip it to divide to get

tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1} which of course simplifies to

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