Use the graph to find the limit (if it exists). If the limit does not exist, explain why.

Mathematics

1 answer:

Mandarinka [93]3 years ago

6 0

Answer:

the limit does not exist

Step-by-step explanation:

As x approaches π/2 from below, tan(x) approaches +∞. A x approaches π/2 from above, tan(x) approaches -∞. These two limits are not the same, so the limit is said not to exist.

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For a limit to exist, it must be the same regardless of the direction of approach.

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One line passes through the points (-7,5)

Studentka2010 [4]

Answer:

1. (-7, 5 ) and (-1, 3)

(3-5)/(-1+7)= -2/6 = -1/3

y - 5 = (-1/3)(x + 7)

y - 5 = (-1/3)x - 7/3

y - 15/3= (-1/3)x - 7/3

y = (-1/3)x + 8/3

2. (-1-3)/(3-0)= -4/3

y + 3 = (-4/3)(x + 1)

y + 3 = (-4/3)x - 4/3

y + 9/3 = (-4/3)x - 4/3

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the answer is neither

7 0

3 years ago

On a number line, what is x-4<-3?

goblinko [34]

Add 4 to both sides

x - 4 < -3

x-4+4 < -3+4

x < 1

To graph this on a number line, plot an open circle at 1 on the number line. Do not fill in the open circle. Shade to the left of the open circle. The shaded region represents all x values smaller than 1.

The graph is shown below.