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Mice21 [21]
3 years ago
7

Describe how you will ensure adequate liquidity to cover anticipated expenses.

Mathematics
1 answer:
GaryK [48]3 years ago
7 0
Describe how you will ensure adequate liquidity
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GIVING 100 POINTS FOR THIS QUESTION PLS PL SPL SPLS PLS HELPPP!!!!! !!
sergiy2304 [10]

Answer: 65000$ worth of things

This is edited, because I got it backwards last time.

We need to make 2500, but she only makes 4% of whatever she sells.

That means the equation is

2500 = 0.04x

Now, we just need to divide both sides by 0.04 and we get 65000.

Sorry for the confusion.

7 0
2 years ago
Which of the following is less than 7/8 and greater than 1/3
Rudiy27
1/2, 2/3, 3/4, 4/5,
7 0
2 years ago
10x + (-8)= -3x + 2<br> How do I solve this in pemda order
larisa [96]

Answer:

x= 10/13

Step-by-step explanation:

First, we need to put the variable on one side and the constants on another side.

Also a positive and a negative equal a negative. [this is related to +(-8)]

10x+(-8)= -3x+2

+3x         +3x

13x-8=2

    +8  +8

13x=10

Finally you divide on both sides

13x/13=10/13

x= 10/13

I hope this is right! I tried my best

4 0
3 years ago
PLEASE HELP NOW --- &gt;N is a 2-digit even number. If the last two digits of N^2 is the same as N, what is the sum of digits of
taurus [48]

Answer:

76.

Step-by-step explanation:

It is given that N is a 2-digit number.

Last two digits of N^2 is the same as N.

We know that, a number is even if it ends with 0,2,4,6,8.

2^2=4,4^2=16,6^2=36,8^2=64

If 0 is in end then we get two zeros in the square of that number.

It is clear that, number should ends with 6 to get the same number at the end.

16^2=256

26^2=676

36^2=1296

46^2=2116

56^2=3136

66^2=4356

76^2=5776

86^2=7396

96^2=9216

It is clear that last two digits of (76)^2 is the same as 76.

Therefore, the required number is 76.

6 0
3 years ago
a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.​
Inessa05 [86]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

A_x=50cos(89.75) so

A_x=.22

B_x=200cos(0) so

B_x=200 and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

C_x=200 (and remember I am counting that as 3 sig fig's even though it's only 1).

Now for the y components:

A_y=50sin(89.75) so

A_y=50 (which I'm counting as 2 sig fig's)

B_y=200sin(0) so

B_y=0 and we need to add those results together.

C_y=50

Now for the resultant magnitude:

C_{mag}=\sqrt{(200)^2+(50)^2}  and that gives us a final magnitude of

C_{mag}=206 m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

tan^{-1}(\frac{50}{200})=14

The girl is 206 meters from her starting point at an angle of 14 degrees

4 0
3 years ago
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