Question

The following equation is true for all real values of k for which the expression on the left is defined, and A

Answer 1

Answer:

A = 6k(k + 6)

Step-by-step explanation:

We have to solve the given equation for the value of A,

$\frac{6k^2-36k}{A}.\frac{k^2+12k+36}{k^2-36}=1$

$\frac{(6k^2-36k)(k^2+12k+36)}{A(k^2-36)}=1$

(6k² - 36k)(k² + 12k + 36) = A(k² -36)

6k(k - 6)(k + 6)² = A(k - 6)(k + 6)

A = $\frac{6k(k-6)(k+6)^2}{(k-6)(k+6)}$

A = 6k(k + 6)

Therefore, value of A is 6k(k + 6).