What is the approximate surface area of a cylinder with a height of 12 meters and a base radius of 2 meters?

2 answers:

5 0

Surface area of a cylinder: 2B + Ch
Word form: 2(area of base) + (circumference of base)(height)

Find the numbers you need to plug in to the formula.

Area of base: $\pi$ 2² = <span>12.57 m</span>²<span>
</span>
Circumference of base: 2 $\pi$ 2 = 12.57 m

Height: 12 m

Plug these numbers in to the formula.
2(12.57) + (12.57)(12) = 175.98

The SA of the cylinder is 175.98 m².

kvasek [131]4 years ago

5 0

A= 2(pi)rh + 2(pi)r^2 = 2•pi•2•12+2•(pi)•2^2 = 175.92919m^2

You might be interested in

Hose 1 in June took 45 mins to fill a pool of height of 20 inches and length 110 inches. Hose 2 in July took 15 mins to fill the

worty [1.4K]

Answer:

there isnt enough evidence to colclude an answer

Step-by-step explanation:

6 0

3 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$