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nexus9112 [7]
2 years ago
13

900.54 hundreds rounded

Mathematics
2 answers:
ehidna [41]2 years ago
7 0

Answer:

100.00 Lol :) hope this helps ⊕∵™

Step-by-step explanation:

yan [13]2 years ago
5 0
901- whole number
900.5- nearest tenth
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Suppose that on each play of a game, a gambler either wins 1 with probability p or loses 1 with probability 1–p (or q). The gamb
musickatia [10]

Answer:

Step-by-step explanation:

From the given information,

Considering both cases when p = 0.5 and when p ≠ 0.5

the probability that the gambler will quit an overall winner is:

P = \dfrac{1 - (\dfrac{1-p}{p} )^K}{1- (\dfrac{1-p}{p})^N } \ \ \  is \  p  \neq 0.5  \  and\  K/N = \dfrac{1}{2}

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Hence, the probability changes to:

P = \dfrac{1 -(\dfrac{1-p}{p})^m}{1 -(\dfrac{1-p}{p})^{m+n}} is  p ≠ 0.5   and k/N = \dfrac{m}{m+n}  is P = 0.5

3 0
3 years ago
Find the equation for the circle with a diameter whose endpoints are (-5, -3) and (3,2).
densk [106]

Answer:

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Step-by-step explanation:

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Then the circle equation is ...

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3 0
3 years ago
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gavmur [86]

\left(\mathrm{Decimal:\quad }x=-0.75\right)



hope it helps :P


4 0
3 years ago
Read 2 more answers
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