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kati45 [8]
3 years ago
14

In the figures below, the cube-shaped box is 6 inches wide and the rectangular box is 10 inches long, 4 inches wide, and 4 inche

s high. How much greater is the volume of the cube-shaped box than the rectangular box? A. 66 cubic inches B. 60 cubic inches C. 56 cubic inches D. 50 cubic inches
Mathematics
1 answer:
olganol [36]3 years ago
7 0
The cube-shaped box has a volume of 216 cubic inches. The rectangular box has a volume of 160 cubic inches. Therefore, the answer is C) 56 cubic inches.
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xeze [42]

Answer:

x=27, y=18

Step-by-step explanation:

Angle CB is 128, which means angle AC is 72. We can confirm angle O is also 72, since the lines are straight. Angle AM is 27, because AN is a right angle. 63+72+27= 162 180-162=18 Angle ND is 18.

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3 years ago
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23q−34) and (−16q−r)
faltersainse [42]

Answer:

r = 7 q - 34

Step-by-step explanation:

Solve for r:

-34 + 7 q - r = 0

Subtract 7 q - 34 from both sides:

-r = 34 - 7 q

Multiply both sides by -1:

Answer:  r = 7 q - 34

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Help Please!!<br> What is the value of a?<br><br> Enter your answer in the box.<br><br> a =
Talja [164]

Answer:

a=15

Step-by-step explanation:

By pythagoras' theorem

25²=20²+a²

625=400+a² group like terms

a²=625-400

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\sqrt{a {}^{2} }  =  \sqrt{225}

therefore a=15

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3 years ago
The following table shows Jace's earnings based on the number of hours that he works.
statuscvo [17]

Answer:

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1 year ago
An object is traveling at a steady speed of 10 1/5 mi​/h. How long will it take the object to travel 1 4/5?
professor190 [17]

The object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi​/h.

<h3>What is the distance?</h3>

Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.

It is given that:

An object is traveling at a steady speed of 10 1/5 mi​/h.

u = 10 1/5 min/h

u = 51/5 min/h

As we know, the speed-distance relationship:

time = distance/speed

distance = 1 4/5 = 9/5

time = (9/5)/(51/5)

time = 9/51 hours

time = (9/51)60

time = 10.58 minutes

Thus, the object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi​/h.

Learn more about the distance here:

brainly.com/question/26711747

#SPJ1

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